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3 years ago

What are some possible replacements for Tin (Sn)?? Help ASAP!!!!!!!!

Chemistry

1 answer:

yulyashka [42]3 years ago

8 0

Answer:

Lead I think is one I'm not completely sure but I know they're similar in some ways

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Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo

Romashka-Z-Leto [24]

Answer:

$\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}$

Explanation:

Volume of a cone:

$\displaystyle V=\frac{1}{3} \pi r^2 h$

We have $\displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec}$ and we want to find $\displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ?$ when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

$\displaystyle V =\frac{1}{3} \pi (5h)^2 h$
$\displaystyle V =\frac{1}{3} \pi \ 25h^3$

Differentiate this equation with respect to time t.

$\displaystyle \frac{dV}{dt} =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}$
$\displaystyle \frac{dV}{dt} =25 \pi h^2 \ \frac{dh}{dt}$

Plug known values into the equation and solve for dh/dt.

$\displaystyle 10 = 25 \pi (2)^2 \ \frac{dh}{dt}$
$\displaystyle 10 = 100 \pi \ \frac{dh}{dt}$

Divide both sides by 100π to solve for dh/dt.

$\displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}$
$\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}$

The height of the cone is increasing at a rate of 1/10π cm per second.

7 0

3 years ago

Balanced equation of potassium chloride and ammonium nitrate; it’s types, net and observation

ASHA 777 [7]

Potassium chloride reacts with ammonium nitrate to give ammonium chloride and potassium nitrate.

This is a type of double displacement reaction. The balanced chemical equation can be represented as,

$KCl(aq)+NH_{4}NO_{3}(aq)-->NH_{4}Cl(aq)+KNO_{3}(aq)$

Total ionic equation for this reaction will be,

$K^{+}(aq)+Cl^{-}(aq)+NH_{4}^{+}(aq)+NO_{3}^{-}(aq)--> K^{+}(aq)+NO_{3}^{-}(aq)+NH_{4}^{+}(aq)+Cl^{-}(aq)$

There is no apparent reaction as this reaction is not accompanied by the formation of a gas or a solid precipitate. We cannot observe any visual reaction as there is not net reaction taking place. All the ions remain as spectator ions.

5 0

3 years ago

Additional Practice Questions

bezimeni [28]

pH of solution = 13.033

<h3>Further explanation</h3>

Given

2.31 g Ba(OH)₂

250 ml water

Required

pH of solution

Solution

Barium hydroxide is fully ionized, means that Ba(OH)₂ is a strong base

So we use a strong base formula to find the pH

[OH ⁻] = b. Mb where

b = number of OH⁻ /base valence

Mb = strong base concentration

Molarity of Ba(OH)₂(MW=171.34 g/mol) :

$\tt M=\dfrac{mol}{L}=\dfrac{2.31~g\div 171.34~g/mol}{0.25~L}\\\\M=0.054$

Ba(OH)₂ ⇒ Ba²⁺ + 2OH⁻(b=valence=2)

[OH⁻]= 2 . 0.054

[OH⁻] = 0.108

pOH= - log 0.108

pOH=0.967

pOH+pH=14

pH=14-0.967

pH=13.033

4 0

2 years ago

An acid with a H+ molarity of 1.4x10^-5 M has a pH of?

gregori [183]

Answer:i created brainly follow me and u grt all the answers u need

Explanation:

7 0

3 years ago

Hey...how do you guys think I could fix a grade of D and F in the 4 weeks I have left? I believe it's possible just need some ti

Sonja [21]

Ok so, it all comes down to basically how nice the teachers are? Go to them and ask them personally if they'd take any late work or makeup work. Also ask (but in a very kiss butt way) if there was any chance theyd be willing to give you extra credit. The key to doing this is like basically just begging them and being super apologetic. Be fake and see if it gets you anywhere?

5 0

3 years ago

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