Answer:
i think it's hydrogen reacts to oxygen
Answer:
An alkali metal present in period 2 have larger first ionization energy.
Explanation:
Ionization energy:
The amount of energy required to remove the electron from the atom is called ionization energy.
Trend along period:
As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.
Trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus. Thus alkali metal present in period 2 have larger ionization energy because of more nuclear attraction as compared to the alkali metal present in period 4.
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In chemistry, neutralization is a chemical reaction in which an acid and a base react quantitatively with each other, and where the final Ph of the solution is neutral (7).
In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present in the solution.
0.1m moles of solute particles are present in 1 L of each of the following aqueous solutions.
The number of moles of solute = mass of solute ÷ molar mass of solute, where mass is measured in grams and molar mass (defined as the mass of one mole of a substance in grams) is measured in g/mol
<h3>What is meant by moles of solute?</h3>
Molality is defined as moles of solute per kilogram of solvent. Molality = mass of solvent (in kg) moles of solute = molecular weight of solute × mass of solvent (in kg) mass of solute.
Learn more about moles of solute here:
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