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Svetllana [295]
2 years ago
8

How do the terms denature, catalyst, active site, and substrate relate to each other

Chemistry
1 answer:
postnew [5]2 years ago
5 0

Explanation:

The enzyme 's active site binds to the substrate. Increasing the temperature generally increases the rate of a reaction, but dramatic changes in temperature and pH can denature an enzyme, thereby abolishing its action as a catalyst. ... When an enzyme binds its substrate it forms an enzyme-substrate complex.

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Based upon the location of group iv on the periodic table, the ionic charge of the elements in it should be:
ruslelena [56]
Periodic table is a table of elements arranged in periods and groups in terms similar chemical and physical characteristics.The ion charge of an element depends on the number of electrons may loose or gain to form a stable ion. Elements in group iv have four electrons in the outermost energy level, therefore their ionic charge would be +4 or - 4 since they can gain or loose 4 electrons to form ions.
3 0
3 years ago
What volume in liters will be occupied by 1.20 moles of helium gas at a pressure of 3.675 atm and 100*C?
lesya [120]

Answer:

V = 121.82 L

Explanation:

Given data:

Number of moles of gas = 1.20 mol

Pressure of gas = 3.675 atm

Temperature = 100°C

Volume occupied = ?

Solution:

Formula:

General gas equation:

PV = nRT

R = general gas constant.

Now we will convert the temperature into kelvin.

100+273 = 373 K

V = nRT/P

V = 1.2 mol × 0.0821 atm.L/mol.K × 373 K / 3.675 atm

V = 447.68 / 3.675 atm

V = 121.82 L

5 0
3 years ago
What is the volume of 24.0 g of oxygen gas at STP?
ikadub [295]

v = 16.8

Hope this helps :)

5 0
3 years ago
How do you become good at math
Veronika [31]
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6 0
3 years ago
Read 2 more answers
Gas is heated from 480. K to 750. K and the pressure is kept constant, what final volume would result if the original volume was
attashe74 [19]
Charles law gives the relationship between volume and temperature of gas.
It states that at constant pressure volume is directly proportional to temperature
Therefore
V/ T = k
Where V - volume T - temperature in kelvin and k - constant
V1/T1 = V2/T2
Parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
Substituting the values in the equation
267 L/ 480 K = V / 750 K
V = 417 L
Final volume is 417 L
8 0
3 years ago
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