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Solnce55 [7]
3 years ago
12

Which of the following statements about air masses is true?

Chemistry
2 answers:
zheka24 [161]3 years ago
7 0

Answer:

The correct answer is: D. Air masses are created by patterns of heating and cooling of the Earth's surface.

Explanation:

aleksandrvk [35]3 years ago
4 0

Answer:

The correct answer is: D. Air masses are created by patterns of heating and cooling of the Earth's surface.

Explanation:

The air masses can be simply be divided into warm and cold ones, further they can be moist or not. The formation of the air masses, be it warm and cold, over the land masses is because of patterns of heating and cooling. This results some areas to produce very large air masses that are cold and dry, like Siberia, or warm and dry large air masses, like Sahara. Also, on a local level there's air masses that develop every day and night, which is noticeable during the night and the morning, where the colder air masses from the mountains move down to the valleys, and the warm air masses from the valleys move up to the mountains. That is a because of the change in the heating and cooling patters that differ during the day and the night.

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ASAP WILL GIVE BRAINLIEST!!
Nataly_w [17]

Answer:

The answer to your question is a) N₂     b) 3.04 g of NH₃

Explanation:

Data

mass of H₂ = 2.5 g

mass of N₂ = 2.5 g

molar mass H₂ = 2.02 g

molar mass of N₂ = 28.02 g

molar mass of NH₃ = 17.04 g

Balanced chemical reaction

                3H₂  +  1 N₂   ⇒   2NH₃

A)

Calculate the theoretical yield 3H₂ / N₂ = 3(2.02) / 28.02 = 0.22

Calculate the experimental yield H₂/N₂ = 2.5/2.5 = 1

Conclusion

The limiting reactant is N₂ (nitrogen) because the experimental proportion was higher than the theoretical proportion.

B)

             28.02 g of N₂ -------------------- (2 x 17.04) g of NH₃

               2.5 g of N₂    --------------------   x

                            x = (2.5 x 2 x 17.04) / 28.02

                            x = 85.2 / 28.02

                           x = 3.04 g of NH₃

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3 years ago
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Explanation:

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3 years ago
Determine the empirical formula of a compound containing 1.71 g of silicon and 8.63 g of chlorine.
Basile [38]

Answer:

The answer to your question is: SiCl₄

Explanation:

Data

amount of Si      1.71 g

amount of Cl     8.63 g

MW Si = 28 g

MW Cl = 35.5

Process (rule of three)

For Si                                                        For Cl

        28 g of Si ------------------ 1 mol                      35.5 g of Cl --------------- 1 mol

          1.71g of Si  ---------------   x                              8.63 g of Cl --------------  x

         x = 1.71 x 1 / 28 = 0.06 mol                          x = 8.63 x 1 / 35.5 = 0.24 mol

Now, divide both results by the lowest of them.

Si = 0.06 mol / 0.06 = 1 molecule of Si     Cl = 0.24 / 0.06 = 4 molecules of Cl

Finally

                     Si₁ Cl₄ or SiCl₄

8 0
3 years ago
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