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saveliy_v [14]
2 years ago
10

Otra manera para llamar la aceleración negativa es_______

Chemistry
1 answer:
enyata [817]2 years ago
8 0

Answer:

creo que es cinemática, eso creo

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If you have 6.02 x 1023 kittens, how many moles of kittens do you have?
ser-zykov [4K]
1 mole= 602,200,000,000,000,000,000,000 its just this huge number! =6.022 x 10 to the power of 23. So that's it I guess!
7 0
3 years ago
PLEASE HELP REALLY IMPORTANT
USPshnik [31]
<span> The temperature of the water in both beakers is greater than 8 °C
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3 years ago
Calculate the number of grams contained in each of the following number of moles. Report your answer with the appropriate number
Debora [2.8K]

<u>Answers:</u>

a. 131.85 grams

b. 134.69 grams

To calculate the number of grams in the number of moles given for each compound, consider the formula:

<em>Moles = No. of grams / molar mass</em>

Therefore, to find the gram it will become:

<em>No. of grams = moles x molar mass</em>

a.  0.410 mol of NaCl (sodium chloride)

Molar mass of NaCl = (286.14 + 35.45) = 321.59

No. of grams = moles x molar mass

No. of grams = 0.410 x 321.59 = 131.85 grams

b. 4.80 mol of C2H4 (ethylene)

Molar mass of C2H4 = (12.01 x 2) + (1.01 x 4) = 28.06

No. of grams = moles x molar mass

No. of grams = 4.80 x 28.06 = 134.69 grams

3 0
3 years ago
Read 2 more answers
Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produce
Diano4ka-milaya [45]
To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:

mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
4 0
3 years ago
PLS HELP The average atomic mass of carbon is 12.01 amu. Based on the atomic
Masteriza [31]

Answer:

B. There is a very large percentage of C-12.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize that, since the average atomic mass is 12.01 amu, then the C-12, with an atomic mass of 12.000 am prevails over C-13 with an atomic mass of 13.003 amu as long as the average is nearer to the former.

In such a way, the answer will be B. There is a very large percentage of C-12.

Regards!

7 0
3 years ago
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