There are 32 atoms
12 in hydrogen
4 in phosphorus
16 in oxygen
molarity = moles of solute/liters of solution
We know the moles of solute: 0.875 moles of glucose. We can easily determine the liters of solution by using the mass of water given (1.5 kg) and the density of water (approximately 1 kg/L): they're, for all intents and purposes, equal (the approximation isn't large enough to be appreciable here, nor would the volume of the solution appreciably change since the solute is a solid that will <em>dissolve into </em>the solvent). So, we have 1.5 L of solution.
Now, we plug in what we have:
molarity = 0.875 moles of glucose/1.5 L of solution = 0.58 M glucose
The answer is provided to two significant figures since we're given the mass of water to two significant figures.
Answer :
Option D) 2.50 X
Mol/(L s)
Explanation: While calculating the average reaction rate for the given reaction in terms of Cl;
![H_{2} + Cl_{2} ----\ \textgreater \ 2HCl](https://tex.z-dn.net/?f=%20H_%7B2%7D%20%2B%20Cl_%7B2%7D%20%20----%5C%20%5Ctextgreater%20%5C%20%202HCl)
.
using the rate equation which is;
![\frac{-1}{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-1%7D%7B1%7D%20)
![\frac{delta [Cl]}{delta t}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdelta%20%5BCl%5D%7D%7Bdelta%20t%7D%20)
=
![\frac{- 0.0875 - 0.0625}{10s - 0s}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-%200.0875%20-%200.0625%7D%7B10s%20-%200s%7D%20)
=
2.50 X
Mol/(L s)
Answer:
2000 mL
Explanation:
Given data:
Number of moles KMnO₄ = 6 mol
Molarity of solution = 3M
Volume of solution in mL = ?
Solution:
Formula:
Molarity = number of moles of solute / volume of solution in L
3 M = 6 mol / volume of solution in L
volume of solution in L = 6 mol/ 3 M
volume of solution in L = 2 L
Now we convert the L into mL:
1 L = 1000 mL
2 L × 1000 mL / 1 L
2000 mL