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ANTONII [103]
3 years ago
7

A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y

-direction. You want to balance the magnetic force with an electric force so that the proton will continue along a straight line.
The electric field should be in the:

a)neg y direction

b)neg x direction

c)postive x direction

d)postive z direction

e)negative z
Physics
1 answer:
Genrish500 [490]3 years ago
8 0

Answer:

Positive z direction.

Explanation:

The magnetic force acting on the electron is given by the formula as :

F=q(v\times B)

q is the charge on proton

v is the speed of proton

B is the magnetic field

It is mentioned that the proton is moving with a velocity in the positive x-direction. The uniform magnetic field B in the positive y-direction such taht,

q = +e

v = vi

B = Bj

F=e(v\ i\times B\ j)

Since, i\times j=k

F=(evB)\ k

So, the magnetic force acting on the proton in positive z axis. Hence, the correct option is (d) "positive z direction".

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Starting at point 0, you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees. What is your heigh
ira [324]

Answer:

43.58 m

Explanation:

If you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees

Using trigonometry ratio

Sin 5 = opposite/hypothenus

Where the hypothenus = 500m

Opposite = height h

Sin 5 = h/500

Cross multiply

500 × sin 5 = h

h = 500 × 0.08715

h = 43.58m

Therefore, the height above the starting point is equal to 43.58m

5 0
3 years ago
QUESTION 3
larisa [96]

Answer:

225 N

Explanation:

Force = Mass . Acceleration

F = 45 . 5

F = 225 N

6 0
2 years ago
Carbon monosulfide ionic or covalent
taurus [48]

Answer:

Covalent.

Explanation:

Carbon and Sulfur are both nonmetals.

Nonmetal+nonmetal= covalent compound.

3 0
2 years ago
You toss a racquetball directly upward and then catch it at the same height you released it 1.82 s later. assume air resistance
Anton [14]
Neglecting air resistance, the acceleration of the ball is
the acceleration of gravity ... 9.8 m/s² downward.

It doesn't matter what you toss, what it's mass is, what it weighs,
what color it is, how much it cost, what its shape or size is, how
fast you toss it, in what direction, or how long it's in the air.

Its horizontal acceleration is zero and its vertical acceleration
is 9.8 m/s² downward, from the moment it leaves your hand
until the moment somebody catches it or it hits the ground.
 
5 0
3 years ago
Question 2 (1 point)
mixer [17]

Answer:

The initial vertical velocity is zero, u = 0 m/s

Explanation:

Given;

height of the table, h = 0.55 m

horizontal distance traveled by the tennis, x = 0.12 m

Apply the following kinematic equation;

h = ut + ¹/₂gt²

where;

u is the initial vertical velocity = 0, since the tennis ball rolled off the edge of a table.

h = ¹/₂gt²

The time to fall from the vertical height is given by;

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2(0.55)}{9.8} }\\\\t = 0.335 \ s

The initial horizontal velocity of the tennis is given by;

x = vₓt

vₓ = x / t

vₓ = (0.12) / (0.335)

vₓ = 0.358 m/s

Therefore, the initial vertical velocity is zero, u = 0 m/s and initial horizontal velocity, vₓ is 0.358 m/s

3 0
3 years ago
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