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ANTONII [103]
3 years ago
7

A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y

-direction. You want to balance the magnetic force with an electric force so that the proton will continue along a straight line.
The electric field should be in the:

a)neg y direction

b)neg x direction

c)postive x direction

d)postive z direction

e)negative z
Physics
1 answer:
Genrish500 [490]3 years ago
8 0

Answer:

Positive z direction.

Explanation:

The magnetic force acting on the electron is given by the formula as :

F=q(v\times B)

q is the charge on proton

v is the speed of proton

B is the magnetic field

It is mentioned that the proton is moving with a velocity in the positive x-direction. The uniform magnetic field B in the positive y-direction such taht,

q = +e

v = vi

B = Bj

F=e(v\ i\times B\ j)

Since, i\times j=k

F=(evB)\ k

So, the magnetic force acting on the proton in positive z axis. Hence, the correct option is (d) "positive z direction".

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Answer:

0.7 m/s

Explanation:

We can solve the problem by using conservation of momentum.

Before the collision, the momentum of the first tackler is:

p_1 = m_1   v_1 =(110 kg)(2.5 m/s)=275 kg m/s

while the momentum of the second tackler is

p_2 = m_2 v_2 =(82 kg)(-5.0 m/s)=-410 kg m/s

Note that we used a negative sign because the direction of the second tackler is opposite to that of the first tackler.

Therefore, the total momentum before the collision is

p_i = p_1 +p_2 =275 kg m/s -410 kg m/s=-135 kg m/s

Since the total momentum is conserved, this is also equal to the final total momentum :

p_f = -135 kg m/s

Which is also equal to

p_f = (m_1 +m_2 )v_f

since the two tacklers continue their motion together with final velocity vf. Re-arranging the previous equation, we can find the the new velocity of the two tacklers:

v_f = \frac{p_f}{m_1 +m_2}=\frac{-135 kg m/s}{110 kg + 82 kg}=-0.7 m/s

and the negative sign means the direction is the one of the second tackler.

3 0
3 years ago
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An elf pushes a sleigh with force of 9N over a distance of 11m. How much work did the elf. Do on the sleigh
Whitepunk [10]

Answer:

<h2>99 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 9 × 11

We have the final answer as

<h3>99 J</h3>

Hope this helps you

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Answer:

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(A) 19.2 W

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