Which metal is most likely to form more than one kind of positively charged ion?

Luke and Sian want to plant a vegetable garden in their yard. A soil testing kit measures the soil pH at 5.0, but the lettuce th

dexar [7]

Answer:

So, Luke and Sian has to increase the pH of the soil by adding base to it.

Explanation:

The pH is defined as the negative logarithm of the hydrogen ion concentration in their aqueous solution.

$pH=-\log[H^+]$

With increase in hydrogen ion concentration the pH value decreases.
With decrease in hydrogen ion concentration the pH value increases.

The pH of the soil after testing it on a kit comes out be 5.0, but they both need pH of the soil to 6.5.

Comparison of pH of soil:

= 5.0 < 6.5

= High hydrogen ion concentration > High hydrogen ion concentration

So, Luke and Sian has to increase the pH of the soil by adding base .Doing so will decrease the hydrogen ion concentration in the soil (where as addition of acid lower the pH of soil).

4 0

3 years ago

Question 231.15 pts A 0.200 M solution of a weak monoprotic acid HA is found to have a pH of 3.00 at room temperature. What is t

MariettaO [177]

Answer:

The correct answer is: Ka= 5.0 x 10⁻⁶

Explanation:

The ionization of a weak monoprotic acid HA is given by the following equilibrium: HA ⇄ H⁺ + A⁻. At the beginning (t= 0) we have 0.200 M of HA. Then, a certain amount (x) is dissociated into H⁺ and A⁻, as is detailed in the following table:

HA ⇄ H⁺ + A⁻

t= 0 0.200 M 0 0

t -x x x

t= eq 0.200M -x x x

At equilibrium, we have the following ionization constant expression (Ka):

Ka= $\frac{ [H^{+}] [A^{-} ]}{ [HA]}$

Ka= $\frac{x x}{0.200 M -x}$

Ka= $\frac{x^{2} }{0.200 M - x}$

From the definition of pH, we know that:

pH= - log [H⁺]

In this case, [H⁺]= x, so:

pH= -log x

3.0= -log x

⇒x = 10⁻³

We introduce the value of x (10⁻³) in the previous expression and then we can calculate the ionization constant Ka as follows:

Ka= $\frac{(10^{-3})^{2} }{0.200 - (10^{-3}) }$ = $\frac{10^{-6} }{0.199}$ = 5.025 x 10⁻⁶= 5.0 x 10⁻⁶

5 0

4 years ago

Read 2 more answers

200.00 grams of an organic compound is known to contain 83.884 grams of carbon, 10.486

ololo11 [35]

The empirical formula of a given compound is C6H9ON5.

<u>Explanation</u>:

Step 1: Obtain the mass of each element present in grams

Element % = mass in g = m

Carbon = 83.884 grams, Hydrogen = 10.486 grams, Oxygen = 18.640 grams, Nitrogen = 86.99 grams.

Step 2: Determine the number of moles of each type of atom present

m/atomic mass = Molar amount (M)

Molar amount of carbon = (83.884 1 mol ) / 12 g = 6.99

Molar amount of hydrogen = (10.486 1 mol) / 1 g = 10.49

Molar amount of oxygen = (18.64 1 mol) / 16 g = 1.17

Molar amount of nitrogen = (86.99 1 mol) / 14 g = 6.21

Step 3: Divide the number of moles of each element by the smallest number of moles

M / least M value = Atomic Ratio (R)

Atomic radius of carbon = 6.99 / 1.17 = 5.9 = 6

Atomic radius of hydrogen = 10.49 / 1.17 = 8.9 = 9

Atomic radius of oxygen = 1.17 / 1.17 = 1

Atomic radius of nitrogen = 6.21 / 1.17 = 5

Step 4: Convert numbers to whole numbers. This set of whole numbers are the subscripts in the empirical formula.

R * whole number = Empirical Formula

The empirical formula of a given compound is C6H9ON5.

7 0

4 years ago

HELPP PLEASEEE I REALLY NEED IT!!!!!!!!

SSSSS [86.1K]

Answer:

Americium is: [Rn]5f^7s^2

Bismuth is: [Xe]6s^24f^145d^106p^3

Tin is: [Kr]4d^105s^25p^2

Vanadium is: [Ar]3d^34s^2

Aluminum is [Ne]3s^23p^1

8 0

3 years ago

Sierra has a special kind of liquid rubber. She knows that ultraviolet light is

lana66690 [7]

Answer:

See explanation

Explanation:

Light is a form of energy. Both ultraviolet light and xrays are part of the electromagnetic spectrum.

As was said in the question, ultraviolet rays is absorbed by the rubber. We must know that prolonged exposure of this piece of rubber to incident ultraviolet light causes the vaporization of volatile materials in the rubber.

When volatile materials in the rubber vaporize, the rubber can become solid. Thus, ultraviolet light can cause rubber to become solid.

However, not all types of light can do this hence it does matter the type of light that falls on the rubber material.

8 0

3 years ago