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Ksivusya [100]
3 years ago
10

It's nighttime, and you ve dropped your goggles into a 3.2-m-deep swimming pool. If you hold a laser pointer 0.90 m above the ed

ge of the pool, you can illuminate the goggles if the laser beam enters the water 2.2 m from the edge. How far are the goggles tfrom the edge of the pool? Express your answer to two significant figures and include the appropriate units
Physics
1 answer:
yanalaym [24]3 years ago
5 0

Answer:

The distance of the goggle from the edge is 5.30 m

Explanation:

Given:

The depth of pool (d) = 3.2 m

let 'i' be the angle of incidence

thus,

i = tan^{-1}(\frac{2.2}{0.90})

i = 67.75°

Now, Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

where,

r is the angle of refraction

n₁ is the refractive index of medium 1 = 1 for air

n₂ is the refractive index of medium 1 = 1.33 for water

now,

1 × sin 67.75° = 1.33 × sin(r)

or

r = 44.09°

Now,  

the distance of googles = 2.2 + d×tan(r)  = 2.2 + (3.2 × tan(44.09°) = 5.30 m

Hence, <u>the distance of the goggle from the edge is 5.30 m</u>

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Good morning.

We have that:

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The acceleration can be found with Newton's Law:

\mathsf{F = m\cdot a\iff a = \dfrac{F}{m}}

Now we put the acceleratin in the velocity equation:

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We want the force, so, let's isolate F:

\mathsf{V\cdot m = F\cdot t}\\ \\ \\ \boxed{\mathsf{F = \dfrac{V\cdot m}{t}}}

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2 years ago
According to Newton's first law of motion, what is required to make an object slow down? Enter your answer in the space provided
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<u>Answer:</u>

According to newton's first law of motion, friction is required to make an object slow down.

<u>Explanation:</u>

According to the Newton's first law of motion, for an object to change its velocity (either a change in the magnitude or the direction), there must be a cause to it which is defined as a net external force.

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3 years ago
Radiation emitted from human skin reaches its peak at λ = 960 µm. what is the frequency of this radiation? planck's constant is
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2) The frequency of this radiation is 313 GHz, and its wavelength 960 \mu m. If we look at the table of the electromagnetic spectrum
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3 years ago
Why are choir concerts better in performance halls than in gymnasiums?
dlinn [17]

Constructive interference in performance halls and the elimination of echoes are reasons why choir concerts better in performance halls than in gymnasiums.

<h3>What is constructive interference?</h3>

Constructive interference is a phenomenon which occurs when two waves travelling in same direction and which are in phase add up together to produce a wave of greater amplitude.

Constructive interference occurs in performance halls while destructive interference occurs in gymnasiums.

Also in performance halls, echoes are minimized due to the padded walls and the curtains while echoes which disturb choir concerts occur in gymnasiums.

Therefore, choir concerts better in performance halls than in gymnasiums because of constructive interference in performance halls and the elimination of echoes.

Learn more about constructive interference and echoes at: https://brainly.in/question/2378717

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