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Amiraneli [1.4K]
3 years ago
5

Identify the structure that protects and gives support to this plant cell.

Chemistry
2 answers:
erik [133]3 years ago
8 0
Cytoskeleton, because skeletons support structures
padilas [110]3 years ago
6 0
Cell wall
Giddy Up!!!!!!!!!!!
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In Period 3, from left to right in order, each successive
emmasim [6.3K]
Here are some trends you should know.
Electronegativity increases as you go right and up along the periodic table.
       So, (1) is wrong
Atomic mass increases as you go right and down along the periodic table.
       So, (2) is wrong
Proton number or atomic number increases as you go right and down in the table.
       So, (3) is correct
Metallic character increases as you go left and down along the periodic table.
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8 0
3 years ago
Read 2 more answers
How does this data provide evidence for base pairing in dna
USPshnik [31]

Answer:

There are chemical cross-links between the two strands in DNA, formed by pairs of bases. They always pair up in a particular way, called complementary base pairing: thymine pairs with adenine (T–A) guanine pairs with cytosine (G–C)

Explanation:

Hope it helps u

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8 0
3 years ago
You have 15.0 L of nitrogen gas at 100°C and 200 kPa. What volume of gas will you have at STP?
Pavel [41]
Actually, you do NOT need to calculate the number of moles, so you do NOT need to convert the volume and pressure. (You DO have to convert the temperature.) That's because for this problem, pV/T is constant, so the units cancel (but the temperature scale matters). 

<span>200kPa * 15L / 373K = 101kPa * V / 273K </span>
<span>V = 21.7 L </span>
7 0
4 years ago
A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

8 0
3 years ago
PLEASE HELP!! WILL MARK BRAINLIEST AND THANK YOU!!!
Pepsi [2]

Answer:8

Everything after the decimal place is a significant figure here

5 0
4 years ago
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