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nika2105 [10]
3 years ago
10

Can someone help, please ??

Chemistry
2 answers:
Yuri [45]3 years ago
8 0
13. The periodic table was discovered by Dalton.
14.NaCl is sodium chloride
Zinaida [17]3 years ago
5 0
Number 13 is D. Mendeleev. He was a Russian chemist and inventor who formulated the periodic table.
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How many mL of 1.76 M sodium hydroxide solution (strong base) must be added to 0.75
erma4kov [3.2K]

Answer: Special care is required to prepare a solution of sodium hydroxide or NaOH in water because considerable heat is liberated by the exothermic reaction. The solution may splatter or boil. Here is how to make a sodium hydroxide solution safely, along with recipes for several common concentrations of NaOH solution.

Explanation:

Hope this helps!

5 0
3 years ago
Ammonia (NH3) is widely used as a fertilizer
ratelena [41]

Answer:

82.28g

Explanation:

Given parameters:

Number of moles of hydrogen gas = 7.26 moles

Unknown:

Amount of ammonia produced = ?

Solution:

We have to write the balanced equation first.

              N₂    +   3H₂    →    2NH₃

Now, we work from the known to the unknown;

   

                  3 moles of H₂ will produce 2 moles of NH₃

                7.26 mole of H₂ will produce \frac{7.26 x 2}{3}  = 4.84 moles of NH₃

Molar mass of NH₃ = 14 + 3(1) = 17g/mol

Mass of NH₃  = number of moles  x molar mass = 4.84 x 17 = 82.28g

3 0
3 years ago
Please help Me Answer this
SOVA2 [1]
Objects that produce heat are coal, liquid fuels, gasoline, oil, and gaseous fuels
8 0
3 years ago
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7) Facilitated diffusion is
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3 0
3 years ago
Complete combustion of 4.40 g of a hydrocarbon produced 14.1 g of co2 and 5.04 g of h2o. what is the empirical formula for the h
andrew11 [14]
For a hydrocarbon, the combustion reactions are the following:

C + O₂ --> CO₂
H₂ + 1/2 O₂ --> H₂O

The molar mass of CO₂ is 44 g/mol while C is 12 g/mol. Let's solve for amount of C in hydrocarbon.

Mass of C = (14.1 g CO₂)(1mol/44g)(1 mol C/1 mol CO₂)(12 g/mol) = 3.845 g C
So, that means that the mass of hydrogen is:
Mass of H = 4.4 - 3.845 = 0.555 g

Moles C = 3.845/12 = 0.32042
Moles H = 0.555/1 = 0.555
Divide both by the smaller value, 0.32042.

C: 0.32042/0.32042 = 1
H: 0.555/0.32042 = 1.732
We have to get an answer that is closest to a whole number. Let's try multiplying both with 4.
C: 1*4 = 4
H: 1.732*4 = 6.93≈7

<em>Thus, the empirical formula is C₄H₇.</em>
3 0
3 years ago
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