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3 years ago

How is the answer A?

Physics

2 answers:

Rudik [331]3 years ago

7 0

Answer:

Explanation:

W = mg

5 = 10m

m = 0.5kg

Dropped from rest,

u = 0

a = 10/6

t = 3

v = u + at

v = 0 + (10/6)3 = 5 m/s

Momentum = mv

= 0.5×5

= 2.5 kgm/s

never [62]3 years ago

4 0

Explanation:

The object's weight on Earth is 5.0 N, so its mass is:

F = ma

5.0 N = m (10 m/s²)

m = 0.50 kg

The acceleration on the moon is g/6 = (10 m/s²) / 6 = 1.67 m/s².

The velocity it reaches after 3.0 seconds is:

v = at + v₀

v = (1.67 m/s²) (3.0 s) + (0 m/s)

v = 5 m/s

So the momentum is:

p = mv

p = (0.50 kg) (5 m/s)

p = 2.50 kg m/s

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3 years ago

A potter's wheel is rotating around a vertical axis through its center at a frequency of 2.0 rev/srev/s . The wheel can be consi

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Explanation:

Given

Frequency of wheel $N_1=2\ rev/s$

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diameter of wheel $d_1=0.30\ m=30\ cm$

radius of wheel $r_1=\frac{d_1}{2}=\frac{30}{2}=15\ cm$

mass of clay $m_2=2.8\ kg$

the radius of the chunk of clay $r_2=8\ cm$

Moment of inertia of Wheel

$I_1=\dfrac{m_1r_1^2}{2}=\dfrac{4.5\times 15^2}{2}\ kg-cm^2$

Combined moment of inertia of wheel and clay chunk

$I_2=\dfrac{m_1r_1^2}{2}+\dfrac{m_2r_2^2}{2}=\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2}\ kg-cm^2$

Conserving angular momentum

$\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow \dfrac{4.5\times 15^2}{2}\cdot 4\pi=(\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2})\omega_2\\\\\Rightarrow \omega _2=\dfrac{4\pi }{1+\dfrac{2.8}{4.5}\times (\dfrac{8}{15})^2}=\dfrac{4\pi}{1+0.1769}=0.849\times 4\pi$

Common frequency of wheel and chunk of clay is

$\Rightarrow N_2=\dfrac{4\pi \times 0.849}{2\pi}=1.698\approx 1.7\ rev/s$

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3 years ago

If you had a known sample of a mineral whose density was 7.1 grams/ml and its volume was 15 ml. What is the mass of the mineral.

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Answer:

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volume = 15 mL

density = 7.1 g/mL

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Read 2 more answers

How is the answer A?​

How is the answer A?