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Leokris [45]
3 years ago
5

Constructive interference occurs when the crests of one wave overlap the crests of another wave. What is the result of construct

ive interference? A. decreased frequency B. increased frequency C. decreased amplitude D. increased amplitude
Physics
2 answers:
Zigmanuir [339]3 years ago
4 0
That would be increased amplitude
GarryVolchara [31]3 years ago
4 0

Answer:

D.

hope this helps

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We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
frez [133]

We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

F_D = c_D A \frac{\rho V^2}{2}

Where,

F_D = Drag Force

c_D = Drag coefficient

A = Area

\rho= Density

V = Velocity

Our values are given by,

c_D = 0.5 (That is proper of a cone-shape)

A = 9m^2

\rho = 1.2Kg/m^3

V = 6.5m/s

Part A ) Replacing our values,

F_D = 0.5*9*\frac{1.2*6.5^2}{2}

F_D = 114.075N

Part B ) To find the torque we apply the equation as follow,

\tau = F*d

\tau = (114.075N)(7)

\tau = 798.525N.m

3 0
3 years ago
How is item A different from Item B?
iris [78.8K]

Explanation:

well there is nothing there and it could be different by diffrent objects, idk

8 0
3 years ago
Read 2 more answers
An automobile traveling 95 km/h overtakes a 1.30-km-long train traveling in the same direction on a track parallel to the road.
SOVA2 [1]

Answer:

Same direction: t=234s; d=6.175Km

Opposite direction: t=27.53s; d=0.73Km

Explanation:

If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be v_{AT}=v_A-v_T (<em>the train must see the car advancing at a lower speed</em>), where v_A is the speed of the automobile and v_T the speed of the train.

So we have v_{AT}=(95km/h)-(75Km/h)=20Km/h.

So the train (<em>anyone in fact</em>) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

t = \frac{L}{v_{AT}} = \frac{1.3Km}{20Km/h} = 0.065h=234s

And in that time the car would have traveled (<em>relative to the ground</em>):

d=v_At=(95Km/h)(0.065h)=6.175Km

If they are traveling in opposite directions, <u>we have to do all the same</u> but using v_{AT}=v_A+v_T (<em>the train must see the car advancing at a faster speed</em>), so repeating the process:

v_{AT}=(95km/h)+(75Km/h)=170Km/h

t = \frac{L}{v_{AT}} = \frac{1.3Km}{170Km/h} = 0.00765h=27.53s

d=v_At=(95Km/h)(0.00765h)=0.73Km

5 0
3 years ago
When two objects collide their momentum after the collision is explained by what?
Gnesinka [82]
<span>When two objects collide their momentum after the collision is explained by</span> the conservation of momentum
5 0
3 years ago
What two forces are balanced in what we call gravitational equilibrium? What two forces are balanced in what we call gravitation
JulijaS [17]

Question:

What two forces are balanced in what we call gravitational equilibrium?

A) the electromagnetic force and gravity

B) outward pressure and the strong force

C) outward pressure and inward gravity

D) the strong force and gravity

E) the strong force and kinetic energy

Answer:

The correct answer is C) Outward Pressure and Inward gravity                                                        

Explanation:

Gravitational equilibrium is a balance between the inward pull of gravity and the outward push of internal gas pressure. It also refers to the condition of a star in which the weight of overlying layers at each point is balanced by the total pressure at that point.

As the weight increases in the lower layers of the sun, the pressure also increases to maintain this balance.   So you find that the outward push of pressure balances the inward pull of gravity thus creating an equilibrium.

Why is gravitational equilibrium important?

The simple answer is <u>balance. </u> If for instance the sun as a stable star (which has gravitational equilibrium) loses it's balance, it becomes highly unstable and prone to violent outbursts. These outbursts are caused by the very high radiation pressure at the star's upper layers, which blows significant portions of the matter at the "surface" into space during eruptions that may rage for several years. Of course such a condition is adverse to the existence and support of life.

Cheers!

6 0
3 years ago
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