The problem can be solve using the formula
τ=r F sin(θ)
Where
τ is the torque,
r is the distance from where the pivot is to where the force
is,
F is the force exerted, and
θ is the angle between the force and radius
τ=(0.15m) (150N) sin(30) = 11.25 Nm
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Answer:
The average induced emf is 29.06 V
Explanation:
Given;
radius of the circular loop, r = 12.0 cm = 0.12 m
magnetic field strength, B = 1.8 T
time interval = 2.8 ms = 0.0028 s
Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²
where;
B is magnetic field
A is area
t is time
substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.
Therefore, the average induced emf is 29.06 V
The SI / Metric unit of force is the ' Newton '.
1 newton is the force that accelerates 1 kg of mass at the rate of 1 m/s² .