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2 years ago

The rms current output in a circuit is 4.67 A. What is the maximum current?

Physics

2 answers:

jek_recluse [69]2 years ago

6 0

Answer:

$I_O = \sqrt2 I_{rms}$

$I_O = \sqrt2 (4.67) = 6.6 A$

Explanation:

As we know that maximum current in AC circuit is related to rms value of the current as per the equation below

$I_{rms} = \frac{I_O}{\sqrt2}$

here the value of maximum current or current amplitude is at numerator.

So in order to find maximum current or current amplitude we can say

$I_O = \sqrt2 I_{rms}$

now plug in the value of rms current in the above equation

$I_O = \sqrt2(4.67)$

$I_O = 6.6 A$

so maximum current is 6.6 A

Mila [183]2 years ago

5 0

Answer:Electrical power consumed by a resistance in an AC circuit is different to the power consumed by a reactance as reactances do not dissipate energy

In a DC circuit, the power consumed is simply the product of the DC voltage times the DC current, given in watts. However, for AC circuits with reactive components we have to calculate the consumed power differently.

Electrical power is the “rate” at which energy is being consumed in a circuit and as such all electrical and electronic components and devices have a limit to the amount of electrical power that they can safely handle. For example, a 1/4 watt resistor or a 20 watt amplifier.

Electrical power can be time-varying either as a DC quantity or as an AC quantity. The amount of power in a circuit at any instant of time is called the instantaneous power and is given by the well-known relationship of power equals volts times amps (P = V*I). So one watt (which is the rate of expending energy at one joule per second) will be equal to the volt-ampere product of one volt times one ampere.

Explanation:

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Three masses are located in the x- y plane as follows: a mass of 6 kg is at (0 m, 0 m), a mass of 4 kg is at (3 m, 0 m), and a m

enot [183]

Answer:

The center of mass of three mass in the x-y plane is located at (1,0.5).

Explanation:

It is given that, a mass of 6 kg is at (0,0), a mass of 4 kg is at (3,0), and a mass of 2 kg is at (0,3). We need to find the center of mass of the system. Center of mass in x direction is :

$C_x=\dfrac{6\times 0+4\times 3+2\times 0}{6+4+2}\\\\C_x=1$

The center of mass in y direction is :

$C_y=\dfrac{6\times 0+4\times 0+2\times 3}{6+4+2}\\\\C_y=0.5$

So, the center of mass of three mass in the x-y plane is located at (1,0.5).

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2 years ago

A sample of copper with a mass of 1.80 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a t

user100 [1]

Answer:

the mass of water is 0.3 Kg

Explanation:

since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:

Q water + Q copper = Q surroundings =0 (insulated)

Q water = - Q copper

since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature

and denoting w as water and co as copper :

m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) = m co * c co * (T co - Ti eq)

m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]

We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C

if we assume that both specific heats do not change during the process (or the change is insignificant)

m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]

m w= 1.80 kg * 0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))

m w= 0.3 kg

7 0

3 years ago

When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less dam

iris [78.8K]

Answer:

Explanation:

Given:

U1 = 1.6 m/s

U2 = -1.1 m/s

M1 = 1850 kg

M2 = 1400 kg

V1 = 0.27 m/s

Using momentum- collision equation,

M1U1 + M2U2 = M1V1 + M2V2

1850 × 1.6 - 1400 × 1.1 = 1850 × 0.27 + 1400 × V2

1420 = 499.5 + 1400V2

V2 = 0.6575 m/s

KE = 1/2 × MV^2

KEa1 + KEa2 = KEb1 + KEb2

Delta KE = KE2 - KE1

KEa1 = 2368 J

KEb1 = 847 J

KEa2 = 67.433 J

KEb2 = 302.6 J

KE1 = KEa1 + KEb1

= 3215 J

KE2 = 370.033 J

Delta KE = -2845 J.

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2 years ago

A- what constant acceleration, in SI units, must a car have to gofrom zero to 60 mph in 10 s?

umka2103 [35]

Answer:

(a) 0.017m/s^2

(b) 17/100,000

Explanation:

(a) speed = 60mph = 60m/1h × 1h/3600s = 0.017m/s, time = 10s

Acceleration (a) = speed ÷ time = 0.017m/s ÷ 10s = 0.0017m/s^2

(b) g = 9.8m/s^2, a = 0.0017m/s^2

a/g = 0.0017/9.8 = 0.00017 = 17/100,000

Distance in foot = 0.17 × 3.2808ft = 0.558ft

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2 years ago

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What is the frequency of a wave that has a wavelength of 2000 meters and is traveling at 20 m/s?

Artist 52 [7]

Answer:

freqiency=velocity/wavelength

ief=20/2000=0.01hz

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2 years ago