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Svetllana [295]
4 years ago
6

A person with his ear to the ground, sees a huge stone strikethe concrete pavement. A moment later two sounds are heard from the

impact: one travels n the air and the other in the concrete, andthey are 2.2 s apart. How far away did the impact occur?
*The speed of sound for air is 343 m/s, for concrete˜3000.
Please show how you set up the problem and how you got youranswer.
Physics
1 answer:
luda_lava [24]4 years ago
7 0

Answer:

852.014 m

Explanation:

The speed of sound in air = 343 m/s = v_a

The speed of sound in concrete = 3000 m/s = v_c

The distance the sound traveled = s

Time between the sounds heard  = 2.2 seconds

Time = Distance / Speed

Time taken by sound travel through air

\frac{s}{v_a}=\frac{s}{343}

Time taken by sound travel through concrete

\frac{s}{v_c}=\frac{s}{3000}

So,

\frac{s}{343}-\frac{s}{3000}=2.2\\\Rightarrow \frac{3000s-343s}{1029000}=2.2\\\Rightarrow \frac{2657s}{1029000}=2.2\\\Rightarrow s=\frac{1029000\times 2.2}{2657}\\\Rightarrow s=852.014\ m

The impact occurs 852.014 m away from the person.

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A crate resting on a rough horizontal floor is to be moved horizontally. The coefficient of static friction is 0.36. To start th
luda_lava [24]

Answer:

Explanation:

The direction of force will be in upward direction making an angle of θ with the vertical .

Reaction force R = mg - F cosθ

Friction force = μR

= .36 (mg - F cosθ )

Horizontal component of applied force

= F sinθ

For equilibrium

F sinθ = .36 (mg - F cosθ)

F sinθ + .36 F cosθ =.36 mg

F (sinθ + .36 cosθ) = .36 mg

F R( cosδsinθ +sinδ cosθ) = .36 mg ( Rcosδ = 1 . Rsinδ= .36 )

F R sin( θ+δ )  = . 36 mg

F = .36 mg / Rsin( θ+δ )

For minimum F , sin( θ+δ ) should be maximum

sin( θ+ δ ) = sin 90

θ+ δ  = 90

Rsinδ / Rcosδ  = .36

δ = 20⁰

θ = 70⁰ Ans

5 0
3 years ago
4. The atmosphere is composed of about 78% nitrogen, 21% oxygen, and 1% argon. Typical atmospheric pressure in Boulder, Colorado
photoshop1234 [79]

<u>ANS</u>

<u>Step</u> <u>1</u> :Explanation of required formula.

According to Dalton's Law of Partial Pressures, the partial pressure of a component of a gaseous mixture depends on the mole ratio of said component and the total pressure of the gaseous mixture

i.e Pi=Xi × Ptotal,

Here we don't know exactly how many moles of the mixture we have,

but we know that 78.0% of all the molecules present in the mixture are nitrogen molecules, 21.0% are oxygen molecules, and 1% are molecules of Ar gas.

As we know, a mole is simply a very large collection of molecules. In order to have one mole of a substance, we need to have 6.022 × 1023 molecules of that substance.

This means that the actual number of moles is not important here, because the ratio that exists between the number of molecules is equivalent to the ratio that exists between the number of moles.

Hence,

<u>Step</u> <u>2</u> : Calculate of mole fraction of the mixture.

mole fraction of nitrogen = 78 /100 = 0.78

mole fraction of O2 =

21 /100 = 0.21

mole fraction of Argon =

1 /100 = 0.01.

<u>Step</u> <u>3</u> : Calculate the pressure contributed by each of the mixture.

The pressure contributed by N2 = mole fraction of N2 × Total pressure = 0.78 × 0.83 atm = 0.6474 atm

The pressure contributed by O2 = 0.21 × 0.83 atm = 0.1743 atm

The pressure contributed by N2 = 0.01 × 0.83 atm = 0.0083 atm.

<u>Tha</u><u>nk</u> <u>You</u> !!!!!!

6 0
3 years ago
2. An 873 kg dragster accelerates at a rate of 44.6 m/s during a race.
Ira Lisetskai [31]

Answer:

<h3>38,673.9N</h3>

Explanation:

According to newton's second law:

Force = mass * acceleration

Given

Mass = 873kg

acceleration = 44.66m/s²

Magnitude of the force is expressed as;

F = ma

F = 873 * 44.6

F = 38,673.9N

<em>Hence the magnitude of the net force exerted on the dragster during this time is 38,673.9N</em>

8 0
3 years ago
An object has an acceleration of 6.0 m/s/s. If the net force was doubled and the mass was one-third the original value, then the
alexandr402 [8]

Hahahahaha. Okay.

So basically , force is equal to mass into acceleration.

F=ma

so when F=ma , we get acceleration=6m/s/s

Force is doubled.

Mass is 1/3 times original.

2F=1/3ma

Now , we rearrange , and we get 6F=ma

So , now for 6 times the original force , we get 6 times the initial acceleration.

So new acceleration = 6*6= 36m/s/s

5 0
4 years ago
What does the ozone layer protect us from?
djyliett [7]
For the future, Put the right subject please, The answer is to protect us from harmful UV rays, Which include UVA, UVB, And UBC.
6 0
3 years ago
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