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2 years ago

What property of water allows it to rise up in a plant

1 answer:

Alex2 years ago

5 0

Transpiration is the evaporation of water through leaf stomata. It is the major force moving water through plants. Cohesion and adhesion create tension within xylem that helps move water upward.

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A toy car with an initial velocity of 5 m/s slows to a stop with an acceleration of -1.5 m/s^2.

enot [183]

Car's Initial velocity (u) = 5 m/s

Car's Final velocity (v) = 0 m/s (Stop)

Acceleration of the car (a) = -1.5 m/s²

Equation used to solve this problem:

$\boxed{ \bf{ {v}^{2} = {u}^{2} + 2as}}$

By substituting values in the equation, we get:

$\rm \longrightarrow {0}^{2} = {5}^{2} +2 \times ( - 1.5) \times s \\ \\ \rm \longrightarrow 0 = 25 - 3s \\ \\ \rm \longrightarrow 25 - 3s = 0 \\ \\ \rm \longrightarrow 25 - 25 - 3s =0 - 25 \\ \\ \rm \longrightarrow - 3s = - 25 \\ \\ \rm \longrightarrow 3s = 25 \\ \\ \rm \longrightarrow \dfrac{3s}{3} = \dfrac{25}{3} \\ \\ \rm \longrightarrow s = 8.3 \: m$

$\therefore$ Displacement of the toy car (s) = 8.3 m

4 0

2 years ago

Determine the ratio of the flow rate through capillary tubes A and B (that is, Qa/Qb).

Oliga [24]

To solve this problem we can use the concepts related to the change of flow of a fluid within a tube, which is without a rubuleous movement and therefore has a laminar fluid.

It is sometimes called Poiseuille’s law for laminar flow, or simply Poiseuille’s law.

The mathematical equation that expresses this concept is

$\dot{Q} = \frac{\pi r^4 (P_2-P_1)}{8\eta L}$

Where

P = Pressure at each point

r = Radius

$\eta =$ Viscosity

l = Length

Of all these variables we have so much that the change in pressure and viscosity remains constant so the ratio between the two flows would be

$\frac{\dot{Q_A}}{\dot{Q_B}} = \frac{r_A^4}{r_B^4}\frac{L_B}{L_A}$

From the problem two terms are given

$R_A = \frac{R_B}{2}$

$L_A = 2L_B$

Replacing we have to

$\frac{\dot{Q_A}}{\dot{Q_B}} = \frac{r_A^4}{r_B^4}\frac{L_B}{L_A}$

$\frac{\dot{Q_A}}{\dot{Q_B}} = \frac{r_B^4}{16*r_B^4}\frac{L_B}{2*L_B}$

$\frac{\dot{Q_A}}{\dot{Q_B}} = \frac{1}{32}$

Therefore the ratio of the flow rate through capillary tubes A and B is 1/32

6 0

3 years ago

Neap tides, relatively weak tides, occur when the Moon is in position(s)

inna [77]

its D. B and D beacuse tthat the neap tides

7 0

3 years ago

When unpolarized light is incident on a sheet of polarizing material with a transmission axis oriented vertically, what percenta

yulyashka [42]

Answer:

If the light were incident upon two polarizers at right angles, no light would get thru - thus each polarizer must block 50% of the light.

One polarizer would allow 50% of the light to pass.

4 0

1 year ago

A block is on a frictionless table, on earth. The block accelerates at 7.5 m/s when a 70 N horizontal force is applied to it. Th

Liono4ka [1.6K]

Answer:

The weight of the block on the moon is 15 kg.

Explanation:

It is given that,

The acceleration of the block, a = 7.5 m/s²

Force applied to the box, F = 70 N

The mass of the block will be, $m=\dfrac{F}{a}$

$m=\dfrac{70\ N}{7.5\ m/s^2}$

m = 9.34 kg

The block and table are set up on the moon. The acceleration due to gravity at the surface of the moon is 1.62 m/s². The mass of the object remains the same. It weight W is given by :

$W=m\times g$

$W=9.34\ kg\times 1.62\ m/s^2$

W = 15.13 N

W = 15 N

So, the weight of the block on the moon is 15 kg. Hence, this is the required solution.

3 0

3 years ago