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liraira [26]
3 years ago
15

There is friction between the block and the

Physics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer:

5 no

Explanation:

actually the 4kg lying on table has no influence

it slides towards 4kg weight hung

as it has excess 2kg force

force=miu × m ×g

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An ethylene glycol solution contains 25.4 g of ethylene glycol (C2H6O2) in 89.0 mL of water. (Assume a density of 1.00 g/mL for
Vaselesa [24]

Answer:

-7.44°C

Explanation:

Calculate the molality of the solution. Use the density of the solvent(water) as a conversion factor in order to convert from millilitres of solvent to grams of solvent. Then convert grams into kilograms. Finally, use the molar mass of ethylene glycol as a conversion factor to convert from grams to moles of ethylene glycol.  

m = 25.4 g C2H6O2/89.0 mL solv

   = 4.6321 C10H8O

Compute the freezing-point depression.  

ΔT_f=K_f*m ==> (1.86°C)*(3.9996 m)

       =7.44°C

Compute the freezing point of the solution by subtracting the freezing-point depression to the freezing point of the pure solvent.  

 freezing point =0.0°C-ΔT_f

                        = -7.44°C

8 0
3 years ago
Can u help pls it’s due now
QveST [7]

Answer:

a.She is moving in a constant speed

b.she is travelling ever 10 minutes every 1 distance

Explanation:

5 0
3 years ago
Which of these is a good example of Newton's First Law of inertia
Eddi Din [679]

Answer: The correct option is A.

Explanation:

Inertia is a state of an object or body to maintain its state. It resists any change in its state.

Newton's first law of inertia: When an objects is in state of motion, it will remain its state of motion or if it is in state of rest then it will remain in rest unless it is acted upon by external motion.

In the given options, a ball sits motionless on the ground is good example of Newton's first law motion. No external force is acting in this case.

In options (B), (C) and (D) , the external force is acting.

Therefore, the correct option is A.

8 0
4 years ago
Read 2 more answers
The Great Sandini is a 60 kg circus performer who is shot from a cannon (actually a spring gun). You don't find many men of his
Alex17521 [72]

Answer:

22m/s

Explanation:

Mass, m=60 kg

Force constant, k=1300N/m

Restoring force, Fx=6500 N

Average friction force, f=50 N

Length of barrel, l=5m

y=2.5 m

Initial velocity, u=0

F_x=kx

Substitute the values

6500=1300x

x=\frac{6500}{1300}=5m

Work done due to friction force

W_f=fscos\theta

We have \theta=180^{\circ}

Substitute the values

W_f=50\times 5cos180^{\circ}

W_f=-250J

Initial kinetic energy, Ki=0

Initial gravitational energy, U_{grav,1}=0\

Initial elastic potential energy

U_{el,1}=\frac{1}{2}kx^2=\frac{1}{2}(1300)(5^2)

U_{el,1}=16250J

Final elastic energy,U_{el,2}=0

Final kinetic energy, K_f=\frac{1}{2}(60)v^2=30v^2

Final gravitational energy, U_{grav,2}=mgh=60\times 9.8\times 2.5

Final gravitational energy, U_{grav,2}=1470J

Using work-energy theorem

K_i+U_{grav,1}+U_{el,1}+W_f=K_f+U_{grav,2}+U_{el,2}

Substitute the values

0+0+16250-250=30v^2+1470+0

16000-1470=30v^2

14530=30v^2

v^2=\frac{14530}{30}

v=\sqrt{\frac{14530}{30}}

v=22m/s

5 0
3 years ago
Why is the surface salinity of the ocean higher in the subtropics than in equatorial regions?
larisa [96]
Evaporation is more contrasted with the rainfall which is less in the correlation of tropical locale. In tropical locale, protection is very little in light of mists. Alongside temperature, it is the main consideration in adding to changes in the thickness of seawater and consequently sea flow. Saltiness is the way to understanding the worldwide water cycle. 97% of the Earth's free water dwells in the seas. The water cycle is commanded by precipitation and evaporation.
7 0
3 years ago
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