Question

in a circuit, a 10 resistor is connected in series to a parallel group containing a 60 resistor and a 5 resistor. what is the total resistance in this circuit?

Answer 1

60 ohm and 5 ohm resistors are in parallel and their parallel combination is given as

$R_{parallel}$  = Product of resistances / (Sum of resistance)

$R_{parallel}$  = 60 x 5 /(60 + 5)

$R_{parallel}$   = 4.62 ohm

The parallel combination of resistances "$R_{parallel}$  " and 10 ohm resistor are in series and their equivalent resistance is given as

$R_{total}$ = $R_{parallel}$  + 10

$R_{total}$ = 4.62 + 10

$R_{total}$ = 14.62 ohm

Answer 2

The 60 and the 5 in parallel have an equivalent resistance of 4.615 ohms. (rounded). The 10 in series makes it 14.615...