Question

In a calorimeter, the temperature of 100g of water decreased by 10 degrees Celsius when 10g of ice melted. How much heat was absorbed by the ice?

Answer 1

So use equation: ΔH = MCΔT

M = mass of water
C = waters specific heat capacity (4.18)
ΔT = the temp. change of the reaction

ΔH = 100 x 4.18 x 10 = 4180J or 41.8KJ

so the cube absorbed 4180J of energy 

hope that helps 

Answer 2

In your question, in a calorimeter, the temperature of 100g of water decreased by 10 degrees celsius when 10g of ice is melted. So so to calculated for the heat that was absorbed by the ice, you must consider the given values that are in the problem and analyze it correctly so the answer is 4180J