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Alenkinab [10]
3 years ago
9

In a calorimeter, the temperature of 100g of water decreased by 10 degrees Celsius when 10g of ice melted. How much heat was abs

orbed by the ice?
Chemistry
2 answers:
Crazy boy [7]3 years ago
6 0
So use equation: ΔH = MCΔT

M 
= mass of water
C 
= waters specific heat capacity (4.18)
ΔT = the temp. change of the reaction

ΔH = 100 x 4.18 x 10 = 4180J or 41.8KJ

so the cube absorbed 4180J of energy 

hope that helps 

AlladinOne [14]3 years ago
3 0
In your question, in a calorimeter, the temperature of 100g of water decreased by 10 degrees celsius when 10g of ice is melted. So so to calculated for the heat that was absorbed by the ice, you must consider the given values that are in the problem and analyze it correctly so the answer is 4180J
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How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K? Report your answer to the nearest mL.
Tcecarenko [31]

1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.00 atm

V= ?

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T=200 K

Putting value in the given equation:

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4 0
2 years ago
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

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number of atoms of gold = 3.47 x 10^{23}

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from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

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rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
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