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Mamont248 [21]
3 years ago
6

A chemical bond is formed between magnesium and chlorine. Describe the process and identify the nature of the chemical bond.

Chemistry
1 answer:
IRINA_888 [86]3 years ago
7 0

Answer:

The answer to your question is: b

Explanation:

a. Magnesium shares an electron somewhat unevenly from its 3s orbital with the 3p orbital of chlorine producing a mildly polar covalent bond.  This option is wrong because Mg does not share electrons it loses electrons.

b. Magnesium loses and electron from the 3s and gives it up to the 3p of chlorine producing an ionic bond.  This option is correct, Mg loses one electron and Cl receives it, the bond formed between Mg and Cl is ionic.

c. Magnesium does not react chemically with chlorine because magnesium gives up electrons, but chlorine only shares electrons.  This answer is wrong, Mg and Cl react and produce MgCl₂.

d. Magnesium shares an electron from the 3s orbital with the 3p orbital of chlorine producing a covalent bond. Mg does not share electrons and is not able to produce covalent bonds.

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Do you think genetic engineering is ethical? Explain why or why not.
kirill [66]

Answer:

Yes

Explanation:

One of the top goals of genetic engineering is the improvement of health. Imagine a world without the threat of AIDS or cancer. Those working in the genetics field hope that manipulating the genes of humans will one day enable science to prevent people from contracting these potentially deadly diseases.

4 0
3 years ago
Sort the sequences based on type of mutation they display.
jarptica [38.1K]

Answer:

There are three types of DNA Mutations: base substitutions, deletions and insertions. Single base substitutions are called point mutations, recall the point mutation Glu -----> Val which causes sickle-cell disease. Point mutations are the most common type of mutation and there are two types.

Explanation:

3 0
2 years ago
Describe, in detail, to a freshman undergraduate how to make 1 liter of LB + Kan (100 μg/ml final concentration) + Amp (50 μg /m
mario62 [17]

Answer:

Explanation:

The objective here is to prepare  1 liter of LB + Kan (100 μg/ml final concentration) + Amp (50 μg /ml final concentration) liquid media.

Given that :

the Stock concentration of Amp: 100 mg/ml (since 1 mg/ml = 1000 μg/ml)

it is required that we convert stock concentration in  μg/ml since 100 mg/ml = 100000  μg/ml

However, using formula C₁V₁=C₂V₂ (Ampicilin),

where:

C₁ = 100000 μg/ml,

V₁=?,

C₂= 50  μg/ml,

V₂=1000 ml

100000 μg/ml × V₁ = 50  μg/ml × 1000 ml

V₁ =  50  μg/ml × 1000 ml/100000 μg/ml

V₁ =   0.5 ml

Given that:

the Stock concentration of Kan: 25 mg/ml (since 1 mg/ml = 1000 μg/ml)

it is required that we convert stock concentration in  μg/ml , 25 mg/ml = 25000 μg/ml

Now by using formula C₁V₁=C₂V₂ (Kanamycin),

C₁ = 25000 μg/ml,

V₁=?,

C₂= 100  μg/ml,

V₂=1000 ml

25000 μg/ml × V₁ = 100  μg/ml × 1000 ml

V₁ =  100  μg/ml × 1000 ml/25000 μg/ml

V₁ =   4 ml

Thus; in 1 lite of Lb+ Kan+Amp preparation;

0.5 ml of Amp & 4 ml of kanamycin is used for their stock preparation.

Finally;

Sterilization step should be carried out in flask (Clean dry glass wares) for media in an autoclave, the container size should be twice the volume of media which is prepared.

5 0
3 years ago
Consider the reaction: AB As the reaction proceeds, the concentration of A drops from 0.625 M to 0.100 Min 11.6 seconds. What is
prisoha [69]

Answer:

0.045 M/s

Explanation:

Given:

Initial concentration of A = 0.625 M

Final concentration of A = 0.100 M

Total time taken for the change of concentration = 11.6 seconds

The average rate of reaction is calculated as:

= \frac{\textup{Change in concentration of A}}{\textup{Time taken for the change}}

on substituting the respective values, we get

= \frac{0.625-0.100}{\textup{11.6}}

or

The average rate of reaction = 0.045 M/s

3 0
3 years ago
If you had done the experiment hands-on and the environmental air pressure changed, how would your results have been affected?
lukranit [14]

Boyle's law states the relationship between pressure and volume of a gas.

From Boyle's law, we know that volume and pressure of a given mass of gas are inversely proportional to each other. Hence, PV = k.

Now, in carrying out this experiment, the atmospheric pressure is assumed to be constant. If the atmospheric pressure changes during the experiment, here would have been a change in the measurements of balloon volume because air pressure changes would have interfered with the results.

Learn more about Boyle's law:  brainly.com/question/1437490

8 0
2 years ago
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