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devlian [24]
3 years ago
5

A stationary rock on a hill has

Physics
2 answers:
Mekhanik [1.2K]3 years ago
5 0

Answer: potential energy but no kinetic energy

Explanation:

Since the rock is stationary, velocity is zero, therefore no kinetic energy,but there's potential energy because the rock is at rest,

Tresset [83]3 years ago
3 0

Answer:

C. Potential energy but no kinetic energy

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(I will give brainliest whoever helps me !!)
lorasvet [3.4K]
C. Forces have mass and take up space
3 0
3 years ago
A ball thrown vertically upward is caught by the thrower after 2.93 s. Find the initial velocity of the ball. The acceleration o
almond37 [142]

Answer:

The initial velocity of the ball is 28.714 m/s

Explanation:

Given;

time of flight of the ball, t = 2.93 s

acceleration due to gravity, g = 9.8 m/s²

initial velocity of the ball, u = ?

The initial velocity of the ball is given by;

v = u + (-g)t

where;

v is the final speed of the ball at the given time, = 0

g is negative because of upward motion

0 = u -gt

u = gt

u = (9.8 x 2.93)

u = 28.714 m/s

Therefore, the initial velocity of the ball is 28.714 m/s

7 0
3 years ago
How does friction help soccer players
Lena [83]
When soccer players run they are using friction to propell themselves
7 0
3 years ago
Read 2 more answers
This is the simplest type of fold where the rock bends like this:
Natasha_Volkova [10]

The answer is Monocline. And I checked it, it's correct.

6 0
3 years ago
Read 2 more answers
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
kati45 [8]

Answer:

The  coefficient of kinetic friction  \mu_k =  0.724

Explanation:

From the question we are told that

   The  length of the lane is  l =  36.0 \  m

    The speed of the truck is  v  =  22.6\  m/s

     

Generally from the work-energy theorem we have that  

    \Delta KE  =   N  *  \mu_k *  l

Here N  is the normal force acting on the truck which is mathematically represented as

     \Delta KE is the change in kinetic energy which is mathematically represented as

        \Delta KE =  \frac{1}{2} *  m *  v^2

=>     \Delta KE =  0.5  *  m *  22.6^2

=>      \Delta KE =  255.38m

        255.38m =    m *  9.8  *  \mu_k *   36.0

=>     255.38  =    352.8  *  \mu_k

=>   \mu_k =  0.724

 

6 0
3 years ago
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