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sp2606 [1]
3 years ago
10

8. While charging the lead storage battery _________ . [NCERT Exemplar] (a) PbSO4 anode is reduced to Pb. (b) PbSO4 cathode is r

educed to Pb. (c) PbSO4 cathode is oxidised to Pb. (d) PbSO4 anode is oxidised to PbO2.
Chemistry
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

(a) PbSO4 anode is reduced to Pb.

Explanation:

Cells which can be recharged are known as secondary cells. They can be recharged by passing a direct current through them. An example of a secondary cell is the lead storage battery used in motor cars.

During the process of recharging, the electrodes in the cell are reversed from what we have  know to occur during discharging because it is electrolized.

At the anode: The lead (II) tetraoxosulphate (VI)  absorbs two electrons to become reduced to Pb. Thus at the anode PbSO₄ is reduced to Pb.

PbSO_4+2e^-\rightarrow Pb+SO_4^{2-}

At the cathode:

The electrons from the anode are accepted at the cathode where the lead (iV) oxide is oxidised into lead (II) ions.

PbSO_4+2H_2O\rightarrow PbO_2+SO_4^{2-}+4H^++2e^-

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Answer:

See below.

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The question is incomplete, here is the complete question:

Problem page in each of the molecules drawn below one chemical bond is colored red. Decide whether this bond is likely to be polar or not. if the bond is likely to be polar, write down the chemical symbol for the atom which will have more negative charge.

The image is attached below.

<u>Answer:</u>

<u>For carbon dioxide molecule:</u> The bond is considered as polar and the elecvtronegative atom is oxygen.

<u>For water molecule:</u> The bond is considered as polar and the elecvtronegative atom is oxygen.

<u>Explanation:</u>

There are two types of covalent bonds:

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  • <u>Non-polar covalent bond:</u> This bond is formed when there is no difference in electronegativity between the atoms. When atoms of the same element combine, it results in the formation of non-polar covalent bond. <u>For Example:</u> N_2,O_2 etc..

<u>In carbon dioxide molecule:</u>

The given bond is present between C and O atom.

Electronegativity value of C = 2.5

Electronegativity value of O = 3.5

Electronegativity difference = (3.5 - 2.5) = 1

As, electronegativity difference is present. So, the bond is considered as polar and the elecvtronegative atom is oxygen.

<u>In water molecule:</u>

The given bond is present between H and O atom.

Electronegativity value of H = 2.1

Electronegativity value of O = 3.5

Electronegativity difference = (3.5 - 2.1) = 1.4

As, electronegativity difference is present. So, the bond is considered as polar and the elecvtronegative atom is oxygen.

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Hope this helps!


:)
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