Answer:
pH = 11.3
Explanation:
From the question given above, the following data were obtained:
Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M
pH =.?
The pH of a solution is defined by the following equation:
pH = –Log [H₃O⁺]
Thus, with the above formula, we can obtain the pH of the solution as follow:
Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M
pH =.?
pH = –Log [H₃O⁺]
pH = –Log 4.950×10¯¹²
pH = 11.3
Answer:
3Zn(s) + 2FeCl₃(aq) → 2Fe(s) + 3ZnCl₂ (aq)
Explanation:
This is a redox reaction where solid iron is formed by the reaction of Zn and Iron(III) chloride. We called redox because the iron is reduced and the zinc is oxidized.
The reactants are: Zn(s) and FeCl₃(aq)
The products are: ZnCl₂(aq) and Fe(s)
Zn(s) → Zn²⁺(aq) + 2e⁻ Oxidation
Fe³⁺(aq) + 3e⁻ → Fe(s) Reduction
The e- are unballanced so we multiply the half reactions:
(Zn(s) → Zn²⁺(aq) + 2e⁻) . 3 → 3Zn(s) → 3Zn²⁺(aq) + 6e⁻
(Fe³⁺(aq) + 3e⁻ → Fe(s)) . 2 → 2Fe³⁺(aq) + 6e⁻ → 2Fe(s)
When we sum the half reactions, the electrons can be cancelled:
3Zn(s) + 2Fe³⁺(aq) + 6e⁻ → 2Fe(s) + 3Zn²⁺(aq) + 6e⁻
Balanced equation: 3Zn(s) + 2FeCl₃(aq) → 2Fe(s) + 3ZnCl₂ (aq)
Rifampin is a nonspecific cyp450 inducer that may induce drugs' metabolism. This can occur when it is <span>coadministered.
Due to this, </span>Rifampin is used as an antibiotic that can treat several bacterial infections including Legionnaire's disease and leprosy.<span>
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Answer:
38 canisters
Explanation:
The combustion of propane can be represented by the equation below:
C₃H₈ (g) + O₂ (g) → CO₂ (g) + H₂O(g) ΔHc = -103.85 kJ/mol
The boiling of water is represented below:
H₂O(l) → H₂O(g) ΔH = Q = mcΔT
The heat necessary to make water reach the boiling point is Q, which is calculated with the mass of water (m = 4.0 kg), its specif heat capacity ( c = 4.200 J/kg°C) and temperature variation (ΔT = 100 - 25)
Therefore, ΔH = Q = 4.0 kg x 4.200 kJ/kg°C x 75 °C
ΔH = Q = 1260.0 kJ
This is the amount of heat necessary to heat the water every day. Since the expedition will last 7 days, the total heat will be 8820 kJ
Now we need to calculate the amount of propane needed to generate this heat:
1 mol C₃H₈ _______ 103.85 kJ
X _______ 8820 kJ
x = 84.9 mol C₃H₈
1 mol C₃H₈ _____ 44 g
84.9 mol C₃H₈ ___ x
x = 3735.6 g
1 canister _____ 100 g C₃H₈
x _____ 3735.6 g
x = 37.3 canisters
The minimum number of fuel canisters I must bring is 38 canisters.