Answer:
15.38 g is the mass for M in the 329 g of sample
Explanation:
Mineral's formula: MS
Our sample weighs 44.9 g
Mass of M: 2.1 g
Our new sample weighs 329 g
We may solve this by a rule of three:
44.9 g of sample contain 2.1 g of M
329 g of sample will contain (329 . 2.1) / 44.9 = 15.38 g
C14H30 because of the formula for alkanes:
CnC2n+2
Answer:
33 g.
Explanation:
Hello there!
In this case, for these particle-mole-mass relationships problems, it is necessary for us to recall the following equivalence statement, based off the molar mass of the involved compound, C3H8, one mole of particles and the Avogadro's number:
In such a way, we can set up the following expression for the calculation of the mass in the given particles of propane:
Best regards!
Matter is everything and everything is made of matter, everything physical at least