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Bas_tet [7]
2 years ago
11

NO LINKS: Which of the following best demonstrates Newton's Third Law?

Physics
1 answer:
irina1246 [14]2 years ago
7 0

The best demonstration that applies to Newton's Third Law of motion would be D) When you walk your foot pushes down on the ground while the ground pushes back on your foot.

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Newton's Third Law states that for every action, there is an equal and opposite reaction. This is actually explains that forces come in pairs and forces are an interaction between two objects. As per the correct option given in the question explains Newton’s Third Law.  

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When you walk your foot (say object A) pushes down on the ground while the ground (say object Q) pushes back on your foot with the same force but in the opposite direction.

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WRONG ANSWERS WILL BE REPORTED
denpristay [2]

Answer:

1 = C

2 = B

Explanation:

6 0
3 years ago
Compare and contrast potential and kinetic energy
inysia [295]
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7 0
3 years ago
Read 2 more answers
The stone falls a further 25 m in the next 1.0 s of its fall. Calculate the stone's average speed during the 3 s of its fall.​
Angelina_Jolie [31]

Answer:

5 minutes sweetheart

Explanation:

thank me later-also give me brainless if you want too when you get the answer correct!

6 0
2 years ago
Two resistors, one with 7.00 Ω of resistance and the other with 11.00 Ω of resistance, are connected in series to a 9.00 V batte
IRINA_888 [86]

Answer:

4.5 W

Explanation:

Applying,

P = V²/(R₁+R₂).................. Equation 1

Where P = Power, V = Voltage, R₁ and R₂ = values of the two resistor.

From the question,

Given: V = 9.00 V, R₁ = 7.00 Ω, R₂ = 11.00  Ω

Substitute these values into equation 1

P = 9²/(7+11)

P = 81/(18)

P = 4.5 Watt.

Hence the power dessipated by the two resistors is 4.5 watt

5 0
2 years ago
A ball is hurled straight up at a speed of 15 m/s, leaving the hand of the thrower 2.00 m above the ground. Compute the times an
SVETLANKA909090 [29]

Answer:

5.37 m/s

0.98 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -9.81\times 10+15^2}\\\Rightarrow v=5.37\ m/s

Velocity of the ball when it passes an observer sitting at a window is 5.37 m/s

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{5.37-15}{-9.81}\\\Rightarrow t=0.98\ s

Time taken by the ball to pass the observer sitting at a window is 0.98 seconds

3 0
3 years ago
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