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tresset_1 [31]
2 years ago
11

Which sentence describes Newton's third law?

Physics
1 answer:
Elena-2011 [213]2 years ago
7 0

Option D. The image shows a pattern made by magnetic field lines around the magnet.

<h3>What is Newton's third of motion?</h3>

Newton's third of motion states that for every action, their is equal and opposite reaction.

When a magnet is placed in a magnetic field, it creates magnetic field lines because it is the region of space where its influence is felt.

Thus, the image shows a pattern made by magnetic field lines around the magnet.

Learn more about magnetic field here: brainly.com/question/7802337

#SPJ1

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A bullet at 800 m/s horizontally hits a target that is 180m away. How far does the bullet fall before it hits the target?
ale4655 [162]
The bullet falls 0.25m

The answer is -0.25m because it is falling, therefore it is negative.
Explanation:

t = dy/vy = 180m/800m/s = 0.23 secs

dy = 1/2 gt^2 = -0.25m
3 0
3 years ago
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The earth's magnetic moment is 8 x 1022 a-m2. If that moment were created by a loop of wire going around the earth (r = 6378 km)
Elena L [17]

Answer:

M = I A      definition of magnetic moment - current * area

A = π R^2 = π * (6.4E6)^2 = 1.3E14 m^2

I = 8E22 A-m^2 / 1.3E14 m^2 = 6.2E8 amperes

I = 620,000,000 amps

4 0
2 years ago
How much force is needed to accelerate a 1,100 kg car at a rate of 1.5 m/s2?
Anna [14]
Assuming there is no force of friction...

F = ma
F = (1300kg)(1.5m/s^2)
F = 1950N
Just multiply mass by acceleration.
1300 x 1.5 = 1950N.
7 0
3 years ago
Position (m)
Elina [12.6K]

Answer:

Image result for position (m) 80 60 40 20 - 20 -40 10 20 30 40 50 time (sec) What is the displacement from 15 to 40 sec? a 20 m b Оооо - 20 m -100 m с 100 m

The average velocity of the object is multiplied by the time traveled to find the displacement. The equation x = ½( v + u)t can be manipulated, as shown below, to find any one of the four values if the other three are known.

Explanation:

3 0
3 years ago
Davisson and Germer performed their experiment with a nickel target for several electron bombarding energies. At what angles wou
pochemuha

Answer:

The angle of diffraction are 67.75 deg and 53.57 deg.

Explanation:

Given:

Davisson and Germer  experiment with nickel target for electrons bombarding.

Voltages : 38\ eV and 54\ eV

We have to find the angles that is  \phi_3_8 and \phi_5_4 .

Concept:

  • Davison Germer experiment is based on de Broglie hypothesis where it says matter has both wave and particle nature.
  • When electrons get reflected from the surface of a metal target with an atomic spacing of D, they form diffraction patterns.
  • The positions of diffraction maxima are given by Dsin(\phi) = n\lambda .
  • An atomic spacing is D = 0.215\ nm, when  the principal maximum corresponds to n=1
  • The wavelength is \lambda, and   \lambda =\frac{1.227 \sqrt{V} } {\sqrt{V_o}}\ nm .

Solution:

Finding the wavelength at V_o=38\ eV .

⇒ \lambda_3_8 =\frac{1.227 \sqrt{V} } {\sqrt{38V}}\ nm

⇒ \lambda_3_8 =0.199 nm

    Plugging the values of wavelength.

⇒  sin(\phi)=\frac{\lambda}{D}

⇒  \phi_3_8=sin^-1(\frac{0.199}{0.215} )

⇒ \phi_3_8 =67.75 degrees.

Now

For for the electrons with energy 54\ eV, V_0=54V the wavelength is.

⇒ \lambda_5_4 =\frac{1.227 \sqrt{V} } {\sqrt{54V}} = 0.173 nm

And

⇒ \phi_5_4=sin^-1(\frac{0.173}{0.215} ) = 53.57 degrees.

So,

The angles of diffraction maxima are 67.75 deg and 53.57 deg.

6 0
3 years ago
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