Answer:
h = 23.716 m
Explanation:
Given that,
The time taken by the stone to hit the water is, t = 2.2 s
Height of the bridge above the ground, h = ?
The distance that the body will fall through the time is given by the formula
S = 1/2 gt² m
Where,
g - acceleration due to gravity
Substituting the values in the above equation
S = 1/2 x 9.8 m/s² x (2.2 s)²
= 23.716 m
Therefore, the height of the bridge from the surface of the water is h = 23.716 m
Theres no data listed below
As this is the projectile motion means the motion of object under constant acceleration, so we use all eq. of motion under constant acceleration.
Angle above horizontal=θ= 35°
Initial speed= v₁ = 25 m/s
Time of flight= t= 2.55 s
Now,
from eq. of motion
x=x₁ + (v₁*cosθ)(t)+1/2 *a*t²
As, there is no acceleration in horizontal direction so a=0 and also initial displacement x₁=0
x= 25*cos(35)*2.55
x=52.22 m
