Answer:
the magnitude of the angular magnification of the telescope. is 4
Explanation:
Calculate the magnitude of the angular magnification of the telescope.
Given that,
distance = 25cm
focal length from the objective f₀ = 20cm
focal length from eye piece f₁ = 5cm
The angular magnification of the telescope is

Magnification = 20 / 5
magnification = 4
Hence, the magnitude of the angular magnification of the telescope. is 4
This is observational learning because Ian observed that his peers waited in the cafeteria until the first bell rings. He decided to imitate them.
Answer:
The speed it reaches the bottom is

Explanation:
Given:
, 
Using the conservation of energy theorem


, 
![m*g*h=\frac{1}{2}*m*(r*w)^2 +\frac{1}{2}*[\frac{1}{2} *m*r^2]*w^2](https://tex.z-dn.net/?f=m%2Ag%2Ah%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2A%28r%2Aw%29%5E2%20%2B%5Cfrac%7B1%7D%7B2%7D%2A%5B%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Ar%5E2%5D%2Aw%5E2)


Solve to w'





The change of state that is occurring is from the liquid state to the solid state.