You have 1 m³ of wood and 1 m³ of aluminum.
Aluminum is the heavier material with a higher density.
What is density?
The mass-to-volume ratio, or mass per unit volume, is known as density. It assesses how much material an object contains in relation to its volume (cubic metre or cubic centimeter). In essence, density is a measurement of how closely together matter is packed.
<u>Density of the wood =1500kg/1m³ = 1500kg/m³ ⟹ 1m³ has a mass of 1500kg Density of Aluminum(Al) =2700kg/m³ = 2700kg/m³⟹ 1m³ has a mass of 2700kg </u>
Therefore, Aluminum is the heavier material with a higher density.
To learn more about density from the given link below,
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<u>Answer:</u> The rate constant for the given reaction is 
<u>Explanation:</u>
For the given chemical equation:
We are given that the above equation is undergoing first order kinetics.
The equation used to calculate rate constant from given half life for first order kinetics:
The rate constant is independent of the initial concentration for first order kinetics.
We are given:
= half life of the reaction = 
Putting values in above equation, we get:
Hence, the rate constant for the given reaction is
The question is incomplete: the complete question is:
Rank molecules or group of molecules by when mammals use as fuel, starting right after meal to only through?
starvation.
a) glucose from glucose-2-phosphate from glycogen.
b) free glucose and amino acids
c) fatty acids from triglycerides
d) glucose produced from amino acids in liver.
Answer:
B
A
C
D
Explanation:
Free glucose and amino acid enters into the blood stream directly and can be used immediately after meals by mammals.
The liver stores excess glucose as glycogen, hence when glucose levels begin to reduce in the body, the pancreas releases glucagon which converts glycogen to glucose.
Triglycerides are broken down to give fatty acids which gives much more energy than glucose.
During starvation, amino acids in the liver is converted to glucose when a person goes for days without eating.
Answer:
a. Rate = k×[A]
b. k = 0.213s⁻¹
Explanation:
a. When you are studying the kinetics of a reaction such as:
A + B → Products.
General rate law must be like:
Rate = k×[A]ᵃ[B]ᵇ
You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.
If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1
Rate = k×[A]¹[B]ᵇ
In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]
Rate = k×[A][B]⁰
<h3>Rate = k×[A]</h3>
b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:
Rate = k×[A]
0.320M/s = k×[1.50M]
<h3>k = 0.213s⁻¹</h3>
