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kumpel [21]
3 years ago
11

What is the magnetic field at the center of a circular loop

Physics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:

The magnetic field at the center of a circular loop is 3.14\times10^{-5}\ T.

Explanation:

Given that,

Radius = 4.0 cm

Current = 2.0 A

We need to calculate the magnetic field at the center of a circular loop

Using formula of magnetic field

B = \dfrac{I\mu_{0}}{2r}

Where, I = current

r = radius

Put the value into the formula

B =\dfrac{2.0\times4\pi\times10^{-7}}{2\times4.0\times10^{-2}}

B =0.00003141\ T

B=3.14\times10^{-5}\ T

Hence, The magnetic field at the center of a circular loop is 3.14\times10^{-5}\ T.

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A child drops a ball from a window.The ball strikes the ground in 3.0 seconds.What is the velocity of the ball the instant befor
lord [1]
It might be 4.0 or 2.22344 seconds as velocity speed
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3 years ago
A wave has a frequency of 6 Hz and a speed of 30 m/s. What is the wavelength of the wave?
Helen [10]

Answer:

D. 5m

Explanation:

fλ = c, where f is frequency, λ is wavelength and c is speed.

6λ=30

λ=30/6=5

5 0
3 years ago
A 7.8 µF capacitor is charged by a 9.00 V battery through a resistance R. The capacitor reaches a potential difference of 4.20 V
Vaselesa [24]

Answer:

655128 ohm

Explanation:

C = Capacitance of the capacitor = 7.8 x 10⁻⁶ F  

V₀ = Voltage of the battery = 9 Volts  

V = Potential difference across the battery after time "t" = 4.20 Volts  

t = time interval = 3.21 sec  

T = Time constant

R = resistance  

Potential difference across the battery after time "t" is given as  

V = V_{o} (1-e^{\frac{-t}{T}})

4.20 = 9 (1-e^{\frac{-3.21}{T}})

T = 5.11 sec  

Time constant is given as  

T = RC  

5.11 = (7.8 x 10⁻⁶) R  

R = 655128 ohm

3 0
3 years ago
Please help on this one?
qwelly [4]

Answer:

D. An image that is smaller than the object and is behind the mirror

5 0
3 years ago
A satellite is spinning at 6.0 rev/s. The satellite consists of a main body in the shape of a sphere of radius 2.0 m and mass 10
bearhunter [10]

Answer:

605447.7066 kgm²/s

Explanation:

m_1 = Mass of sphere = 10000 kg

m_2 = Mass of rod = 10 kg

r = Radius of sphere = 2 m

l = Length of antenna = 3 m

Angular speed

\omega=6\times 2\pi\\\Rightarrow \omega=37.69911\ rad/s

Angular momentum is given by

L=I\omega

Moment of inertia of the satellite is

I_s=\frac{2}{5}m_1r^2

Moment of antenna of the satellite is

I_a=\frac{1}{3}m_2l^2

The angular momentum of the system is

L=I_s\omega+I_a\omega\\\Rightarrow L=\left(\frac{2}{5}m_1r^2+2\times \frac{1}{3}m_2l^2\right)\omega\\\Rightarrow L=\left(\frac{2}{5}10000\times 2^2+2\times \frac{1}{3}\times 10\times 3^2\right)\times 37.69911\\\Rightarrow L=605447.7066\ kgm^2/s

The angular momentum of the satellite is 605447.7066 kgm²/s

5 0
3 years ago
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