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2 years ago

What is the magnetic field at the center of a circular loop

Physics

1 answer:

Elan Coil [88]2 years ago

7 0

Answer:

The magnetic field at the center of a circular loop is $3.14\times10^{-5}\ T$ .

Explanation:

Given that,

Radius = 4.0 cm

Current = 2.0 A

We need to calculate the magnetic field at the center of a circular loop

Using formula of magnetic field

$B = \dfrac{I\mu_{0}}{2r}$

Where, I = current

r = radius

Put the value into the formula

$B =\dfrac{2.0\times4\pi\times10^{-7}}{2\times4.0\times10^{-2}}$

$B =0.00003141\ T$

$B=3.14\times10^{-5}\ T$

Hence, The magnetic field at the center of a circular loop is $3.14\times10^{-5}\ T$ .

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How did Albert Einstein come up with 3 = mc square pls help

inysia [295]

Answer: He came up with this by using theories like the photoelectric effect, the second offered experimental proof of the existence of atoms, and the third introduced the theory of special relativity.

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2 years ago

Which FBD would represent a car moving right with a motor force of 250 N, and force of friction of 750N, a weight of 8500N and a

babymother [125]

Answer:

Option C

Explanation:

Given that

Motor force is 250 N

Force of friction is 750 N

Weight is 8500 N

And, the normal force is 8500 N

Now based on the above information

Here length of the rector shows the relative magnitude forward force i.e. 250 N i..e lower than the frictional force i.e. backward and weight i.e. 8500 would be equivalent to the normal force

8 0

2 years ago

The age of the universe is around 100,000,000,000,000,000s. A top quark has a lifetime of roughly 0.000000000000000000000001s. W

Maslowich

Answer:

10⁴¹ s quark top lives have been in the history of the universe.

Explanation:

You need to determine how many quark top lives there have been in the history of the universe, that is, what is the age of the universe divided by the lifetime of a top quark. Expressed in a formula, this is:

$t\frac{Age of the universe}{Lifetime of a top quark}$

Yo know that the "Age of the universe" is 100,000,000,000,000,000 which can also be expressed as 10¹⁷ s .

You also know that the "Lifetime of a top quark" is 0.000000000000000000000001 which can also be expressed as 10⁻²⁴ s.

Then $t=\frac{10^{17} }{10^{-24} }$

Recalling that the result of dividing two powers of the same base is another power with the same base where the exponent is the subtraction of the initial exponents, it is possible to calculate this division as follows:

$t=10^{17-(-24)}$