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Lina20 [59]
2 years ago
8

If

Physics
1 answer:
iren [92.7K]2 years ago
3 0

Answer:

7n

Explanation:

add the 2 numbers together

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The lower the angle of the slope, ________ the acceleration along the ramp, therefore, the speed at the bottom of a slope will b
pogonyaev

Answer:

Lower

Lower

gsintheta (gsinθ)

Explanation:

The sum of forces resolved parallel to the inclined plane is given by;

F - mgsinθ = 0

ma - mgsinθ = 0

ma = mgsinθ

a = gsinθ

Acceleration is proportional to angle of inclination, thus the lower the angle of the slope, lower the acceleration along the ramp.

therefore, the speed at the bottom of a slope will be lower, (velocity is directly proportional to acceleration) and, consequently, the control will be better.

The acceleration along the ramp, is gsintheta (gsinθ)

3 0
3 years ago
The organ system that moves blood around your body?
dusya [7]
The cardiovascular system moves blood through hour body. It is made up of the Heart pumping the blood that is circulated around the body through its networks of arteries, veins and capillaries. The cardiovascular and lymphatic systems together make up the circulatory system.
3 0
3 years ago
A body is moving with a uniform acceleration of 2m/s² what does it mean?​
Nastasia [14]

Answer:

the body has energy due to its constant motion. it means it moves in a uniform acceleration which has zero velocity

Explanation:

Uniform or constant acceleration is a type of motion in which the velocity of an object changes by an equal amount in every equal time period.

7 0
3 years ago
A ball is launched from ground level at 20 m/s at an angle of 40° above the
DedPeter [7]

(a) The ball's height <em>y</em> at time <em>t</em> is given by

<em>y</em> = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :

0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )

<em>t</em> = 0   or   (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0

The first time refers to where the ball is initially launched, so we omit that solution.

(20 m/s) sin(40º) = 1/2 <em>g t</em>

<em>t</em> = (40 m/s) sin(40º) / <em>g</em>

<em>t</em> ≈ 2.6 s

(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So

0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>

where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :

<em>y</em> = ((20 m/s) sin(40º))² / (2<em>g</em>)

<em>y</em> ≈ 8.4 m

8 0
2 years ago
The last is 80 meter per second,please in am in exam​
inna [77]

Answer:

  1. I have fond the answer

Explanation:

but my camera doesn't work

7 0
3 years ago
Read 2 more answers
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