Name four products of incomplete combustion.

Which body part is proximal to the hip?<br> O elbow<br> O foot<br> O knee<br> O shoulder

fgiga [73]

Answer:

elbow

Explanation:

These terms are replaced by: Proximal: Closer to the point of attachment with the torso. In other words, closer to the shoulder or the hip. The elbow is proximal to the wrist.

6 0

3 years ago

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Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.

weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0

4 years ago

For the reaction 4 Fe + 3 O2 -> Fe2 O3, explain how you would calculate the moles of iron needed to make 10 moles of Fe2O3

Hatshy [7]

Answer:

20 moles

Explanation:

4 Fe + 3O₂ → Fe₂O₃

The chemical equation provided is not yet balanced so let's start by balancing it.

4 Fe + 3O₂ → 2 Fe₂O₃

The equation is now balanced with 4 Fe atoms and 6 O atoms on both sides of the equation. It is important to ensure that the chemical equation is balanced, as only then will it tell you the relationship of the reactants and products in terms of mole.

Looking at the coefficients of Fe and Fe₂O₃, 4 moles of Fe is needed to make 2 moles of Fe₂O₃.

This can be simplified into the mole ratio below.

Fe: Fe₂O₃= 2: 1

This means that for every mole of Fe₂O₃, twice the amount of Fe (in moles) is needed.

Thus for 10 moles of Fe₂O₃,

amount of Fe needed

= 10 ×2

= 20 moles

3 0

3 years ago

When metals combine with nonmetals, the metallic atoms tend to 1. lose electrons and become positive ions 2. lose electrons and

Vika [28.1K]

The correct answer is 1. Lose electrons and become positive ions.

I hope my answer was beneficial to you! c:

5 0

3 years ago

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In what way is the Moon like the Earth?

Svetlanka [38]

Answer:

The Moon has an atmosphere.

Explanation:

The Moon has an atmosphere, but it is very tenuous. Gases in the lunar atmosphere are easily lost to space. Because of the Moon's low gravity, light atoms such as helium receive enough energy from solar heating so that they escape in just a few hours.

5 0

3 years ago