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ivanzaharov [21]
3 years ago
5

Please help me it’s just that I can’t remember how to do this it’s about the Mole and Stoichiomerty

Chemistry
1 answer:
joja [24]3 years ago
8 0

Answer:

6.52moles of H2O

Explanation:

First, let us calculate the number of moles of O2 containing 1.96x10^24 molecules. This is illustrated below:

1mole of O2 contains 6.02x10^23 molecules.

Therefore Xmol of O2 contain 1.96x10^24 molecules i.e

Xmol of O2 = 1.96x10^24/6.02x10^23 = 3.26moles

Now let us generate a balanced equation for the formation of water. This is illustrated below:

2H2 + O2 —> 2H2O

From the equation,

1mole of O2 produced 2moles of H2O.

Therefore, 3.26moles of O2 will produce = 3.26 x 2 = 6.52moles of H2O

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Describe the benefits and the drawback of natural gas.
Finger [1]

When looking to power your equipment or vehicle with natural gas, the first question that springs to mind is: what is natural gas? A lot of people use natural gas in their homes for cooking and heating, but they don’t really give it some thought. So, let’s see what natural gas is and how it’s different from other forms of fossil fuels like oil and coal.

Natural Gas is a fossil fuel that exist in a gaseous state and is composed mainly of methane (CH4) a small percentage of other hydrocarbons (e.g. ethane). The use of natural gas is becoming more and more popular as it can be used with commercial, industrial, electric power generation and residential applications.


5 0
3 years ago
A different mass of sodium hydroxide was used to make another 25.0 cm' solution.
Dmitriy789 [7]

0.003 moles of NaOH was used in the titration.

<h3>What is titration?</h3>

The concentration of an identified analyte can be found using a simple laboratory technique called titration. As a standard solution with a given concentration and volume, a reagent known as the titrant or titrator is created.

By using a solution with a known concentration to measure the concentration of an unknown solution, this process is known as titration. To a known volume of the analyte (the unknown solution), the titrant (the known solution) is typically added from a buret until the reaction is finished. To ascertain the unknown concentration of an identifiable analyte, titration, commonly referred to as titrimetry, is a widely used quantitative laboratory analytical technique (Medwick and Kirschner, 2010). Volume measurements are a crucial component of titration

Concentration in mol/dm3 =

Amount of solution mol

= concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide

= 0.100 × 0.0250

= 0.00250 mol

To know more about titration, visit:

brainly.com/question/27394328

#SPJ9

6 0
1 year ago
Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and
blondinia [14]

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g;     Hydrogen H = 2.24 g     Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon

For Hydrogen:

=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen

For Oxygen:

=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon

For Hydrogen:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen

For Oxygen:

\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen

Thus, the empirical formula is HCO₂

4 0
3 years ago
How many carbon atoms are there in 2 molecules of CCI
Anettt [7]

Answer:

Explanation:

No moraculos si a minha memoria não me trai acho temus 2tomos d carbono

4 0
3 years ago
at what temperature in celsius would a gas have volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a p
Alex

Answer:

initial temperature=-3.31^{\circ}C

Explanation:

Assuming that the given follows the ideal gas nature;

P_1=0.723atm

V_1=13.5L

T_1=?

P_2=0.612atm

V_2=17.8L

T_2=28 ^{\circ}C =273+28K=301K

mole of gass will remain same at any emperature:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

putting all the value we get:

T_2 =269.7K =-3.31 ^{\circ} C

initial temperature=-3.31^{\circ}C

6 0
3 years ago
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