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musickatia [10]
4 years ago
15

Prof. Kopp is working on an experiment located in an abandoned mine near Duluth, MN. The experiment is located approximately 713

m below the surface. He went to visit the site this last summer and took a harrowing ride in a bumpy, claustrophobic elevator down to the cavern. He timed the ride to last about 90 s. Compute the average speed of the elevator (in mph) as it plummeted to the bottom of the shaft.
Physics
1 answer:
MA_775_DIABLO [31]4 years ago
8 0

Answer:

The average speed of the elevator going down in the abandoned mine is 17.722mph.

Explanation:

If the elevator takes 90 seconds to descend a height of 713m, the average speed of the elevator is:

v_{av}=x_T/t_T=713m/90s=7.922m/s

And if 1m/s is 2.23694mph, the average speed is:

v_{av}=7.922m/s=17.722mph.

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Answer:

Evaporation

Explanation:

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A car moves along an x axis through a distance of 900 m, starting at rest (at x = 0) and ending at
OlgaM077 [116]
A car moves along an x axis through a distance of 900 m, starting at rest (at x = 0) and ending at rest (at x = 900 m). Through the first 1/4 of that distance, its acceleration is +6.25 m/s2. Through the next 3/4 of that distance, its acceleration is -2.08 m/s2. What are (a) its travel time through the 900 m and (b) its maximum speed? 

<span>Solve for the time at the 1/4 mark. That's 225 m. How? d = (1/2)at^2 ( initial velocity zero). Thus 225 = (1/2) 6.25 t^2. t^2 = ( 225 * 2 ) / 6.25. t = 8.5 sec. </span>

<span>At the other end t^2 = (675 * 2) / 2.08 -- we reversed the sign and ran time backwards. t = 25.5 sec. </span>

<span>So total time is 8.5 + 25.5 or 34 sec. </span>

<span>Since zero initial velocity: v^2 = 2 a d. Here, v^2 = 2 * 6.25 * 225. v = 53 m/s. That's the fastest speed since braking then occurs.</span>
7 0
4 years ago
Scientists in the laboratory create a uniform electric field e⃗ = 6. 0×105 k^v/m in a region of space where b⃗ =0⃗
zvonat [6]

Scientist in the laboratory create uniform electric field.

PART A: The electric field in rocket frame is  (0,0,  6.0 × 10 ⁵).

PART B: The magnetic field in the rocket frame is  7.3 × 10⁻⁶ j∧  .

<h3>What is uniform electric field?</h3>

The electric field whose strength is not changing with respect to time is called uniform magnetic field.

The electric field is 6.0 × 10 ⁵ k^v/m and the magnetic field is zero.

E' = E + (V×B)

    = 6.0 × 10 ⁵ + (1.1 × 10⁶ × 0)

E' = 6.0 × 10 ⁵ k∧

(Ex , Ey, Ez) = (0,0,  6.0 × 10 ⁵)

The new magnetic field is represented as

B' = B - 1 /c²(v × E)

   =0 - 1 / (3× 10⁸)²(1.1 × 10⁶ i∧ × 6.0 × 10 ⁵k∧ )

B' = 7.3 × 10⁻⁶ j∧

PART A: The electric field in rocket frame is  (0,0,  6.0 × 10 ⁵).

PART B: The magnetic field in the rocket frame is 7.3 × 10⁻⁶ j∧ .

Learn more about uniform electric field.

brainly.com/question/26446532

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7 0
2 years ago
A cylindrical wire made of an unknown alloy hangs from a support in the ceiling. You measure the relaxed length of the wire to b
IceJOKER [234]

Answer: hello  some of your values are wrongly written hence I will resolve your question using the right values

answer:

stiffness =  1.09 * 10^-6 N/m

Explanation:

Given data:

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radius of wire ( r ) = 3.5 m

mass ( m ) = 5kg

<u>Distance stretched (  Δl ) = 4 * 10^-3 m </u> ( right value )

<u>average bond length ( between atoms ) = 2.3 * 10^-10 m </u>( right value)

first step : calculate the area

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        γ          = MgL / A Δl

                    = [ (5 * 9.81 * 16 ) / ( 38.48 * (4.3*10^-3) ) ]

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pav-90 [236]
<h2>Answer: process of converting matter into energy</h2><h2></h2>

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Then, with this division a great release of energy occurs and the emission of two or three neutrons, other particles and gamma rays.  

This means fission is a process in which energy is released by  the separation of the components of the nucleous of the atom.

In other words:

<h2>Matter is converted to energy .</h2>

6 0
3 years ago
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