Answer:
2274 J/kg ∙ K
Explanation:
The complete statement of the question is :
A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at 15 °C. In a few minutes, she measures the final temperature of the system to be 40.0°C. What is the specific heat of the 400.0-g piece of metal, assuming that no significant heat is exchanged with the surroundings? The specific heat of this aluminum is 900.0 J/kg ∙ K and that of water is 4186 J/kg ∙ K.
= mass of metal = 400 g
= specific heat of metal = ?
= initial temperature of metal = 100 °C
= mass of aluminum cup = 100 g
= specific heat of aluminum cup = 900.0 J/kg ∙ K
= initial temperature of aluminum cup = 15 °C
= mass of water = 500 g
= specific heat of water = 4186 J/kg ∙ K
= initial temperature of water = 15 °C
= Final equilibrium temperature = 40 °C
Using conservation of energy
heat lost by metal = heat gained by aluminum cup + heat gained by water

Answer:
Quick maths
First you find the fafarick and the lalickc and the caprisum and the joinnt
No, the density of diamond and graphite would not be the same
Explanation:
What is density?
Density is the amount of substance per unit volume. It is simply mass divided by volume.
Density is greatly influenced by the way substances are packed.
Substances that are well packed will have lower volume for the same amount of matter than another that is poorly packed.
- The carbon atoms in graphite are poorly packed. They are arranged layers upon layers.
- Diamond carbon atoms have a cross-linked networked pattern. They are well packed.
- For the same mass of matter, graphite will take up more space than diamond.
Since:
Density = 
The one that has a lesser volume will have a higher density.
Therefore diamond will have a higher density.
learn more:
Density brainly.com/question/5055270
#learnwithBrainly
There's supposed to be a blank in the statement, where the answer is supposed to be inserted.
The question is supposed to say: "A wave is a disturbance that carries ______ from one place to another through matter or space".
To answer the question, write the word "<em>energy</em>" in the blank.