On rotating the parallelogram with an angle of 180°, we can observe a coincidence between the image of parallelogram with its preimage. Hence, option (C) is correct.
The given problem is based on the fundamentals of parallelogram. A figure having four non-intersecting sides, such that each sides are opposite to each other are known as a parallelogram. For example - Rectangle, Square and Rhombus are the parallelogram.
- The meaning of Rotation is that the angle through which geometrical shape is Rotated. The Preimage and Image are Congruent after Rotation.
- It is given that ,a parallelogram rotates about its center. So, a complete revolution of parallelogram will execute an angle of 360°.
- So on Rotating the Parallelogram through Different angles that is 90°,180°,270°,and found that when the angle is 180°, the parallelogram coincide with its preimage.
Thus, we can conclude that on rotating the parallelogram with an angle of 180°, we can observe a coincidence between the image of parallelogram with its preimage.
Learn more about the parallelogram here:
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Answer:
5.3 × 10^(-8) m
Explanation:
We are given;
Shear force; F = 400 N
Length of cube; L_o = 30 cm = 0.3 m
Shear modulus; S = 2.5 × 10^(10) N/m²
Now,the resulting relative displacement can be gotten from the formula;
F = A × S × Δx/L_o
Where Δx is resulting relative displacement
A is area.
Area of cube = (L_o)² = 0.3² = 0.09
Thus, making Δx the subject, we have;
Δx = (F × L_o)/(A × S)
Plugging in the relevant values;
Δx = (400 × 0.3)/(0.09 × 2.5 × 10^(10))
Δx = 5.3 × 10^(-8) m
Answer:
Explanation:
given,
vector product 
= 
now, expanding the vector
the vector product is equal to
Given Information:
Mass of electron = m = 9x10⁻³¹ kg
initial speed of electron = v₁ = 0.92c
Force = F = 1.4x10⁻¹³ J
Distance = d = 3 m
Required Information:
Final speed of electron = v₂ = ?
Answer:
Final speed of electron = v₂ = 2.974x10⁸ m/s
Explanation:
As we know from the conservation of energy,
E₂ - E₁ = W
E₂ = E₁ + W
Where E₂ is the final energy of electron and E₁ is the initial energy of electron
The above equation can be written in the form of particle energy
γ₂mc² = γ₁mc² + W
where γ₁ and γ₂ are given by
γ₁ = 1/√1 - (v₁/c)²
γ₂ = 1/√1 - (v₂/c)²
First calculate γ₁
γ₁ = 1/√1 - (0.92c/c)²
γ₁ = 2.55 m
Now calculate γ₂
γ₂ = (γ₁mc² + W)/mc²
First we need to find the work done
W = F*d
W = 1.4x10⁻¹³*3
W = 4.2x10⁻¹³ J
so γ₂ is
γ₂ = (2.55*9x10⁻³¹*(3x10⁸)² + 4.2x10⁻¹³)/9x10⁻³¹*(3x10⁸)²
γ₂ = 7.73
Now we can find the new speed of the electron
γ₂ = 1/√1 - (v₂/c)²
Re-arranging the above equation results in
v₂ = c*√(1 - 1/γ₂²)
v₂ = 3x10⁸*√(1 - 1/7.73²)
v₂ = 2.974x10⁸ m/s
Momentum = mass • velocity
M = m • v
Speed is a scalar quantity
Velocity is a vector quantity
That is truly the only difference
