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o-na [289]
3 years ago
10

"An unsaturated solution is formed when 80 grams of salt is dissolved in 100 grams of water at 40° celsius. This salt could be..

. "
1. KNO3 2. KCL 3. NaNO3 4. NaCL
>>>I know the answer is NaNO3 however I do not know how to arrive at this answer. NaNO3 on the graph (Table G - Solubility Curves at Standard Pressure) is above the line which would make supersaturated. Why is this the answer?
Chemistry
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

3. NaNO3

Explanation:

Below the line on TABLE G in the reference tables at 40C

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Calculate the number of grams of sulfuric acid in 1 gallon of battery acid if the solution has a density of 1.25 g/mL and is 37.
loris [4]

Answer:

break it down and just put the numbers

Explanation:

4 0
3 years ago
Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch
barxatty [35]

Answer: 353.6 g.


Explanation:


1) Word equation (given)

Sodium phosphate + calcium choride → sodium chloride + calcium phosphate


2) Balanced chemical equation

2 Na₃PO₄ +3 CaCl₂ → 6 NaCl + Ca₃(PO4)₂


3) Mole ratio

2 moles Na₃PO₄ : 3 moles CaCl₂ :  6 moles NaCl : 1 mole Ca₃(PO4)₂


4)  Formula to convert grams to moles

number of moles = mass in grams / molar mass


5) Number of moles of limiting reactant

a) mass in grams = 379.4 g CaCl₂

b) molar mass CaCl₂ = 110.98 g/mol

c) number of moles CaCl₂ = 379.4 g / 110.98 g/mol = 3.419 moles


6) Theoretical yield of Ca₃(PO4)₂

    3 moles CaCl₂ / 1 mole Ca₃(PO4)₂ = 3.419 moles CaCl₂ / x ⇒

    x = 3.419 × 1 / 3 = 1.140 moles Ca₃(PO4)₂


7) Convert 1.140 moles Ca₃(PO4)₂

a) molar mass Ca₃(PO4)₂ = 310.1767 g/mol

b) mass in grams = number of moles × molar mass = 1.140 moles × 310.1767 g/mol = 353.6 g ← answer.

7 0
3 years ago
If the vapor pressure of ethanol at 34.7degree C is 100
saw5 [17]

Answer:

we will use the Clausius-Clapeyron equation to estimate the vapour pressures of the boiling ethanol at sea level pressure of 760mmHg:

 ln (P2/P1) = \frac{ΔvapH}{R}([tex]\frac{1}{T1}-\frac{1}{T2})

where

P1 and P2 are the vapour pressures at temperatures  T1 and T2

Δ vapH  = the enthalpy of vaporization of the ETHANOL

R  = the Universal Gas Constant

In this problem,

P 1 = 100 mmHg

;  T 1 = 34.7 °C = 307.07 K

P 2 = 760mmHg

T 2 =T⁻²=?

Δ vap H = 38.6 kJ/mol

R = 0.008314 kJ⋅K -1 mol -1

ln ( 760/10)=(0.00325 - T⁻²) (38.6kJ⋅mol-1 /0.008314 )

0.0004368=(0.00325 - T⁻²)  

T⁻²=0.002813

T² = 355.47K

6 0
3 years ago
How many electrons must calcium lose to satisfy the octet rule?
earnstyle [38]

Answer:

Lose 2 electrons

Explanation:

8 0
3 years ago
Fdsddddgdgdgdgsdggd.
larisa [96]
Fdsddadgdsadgsd:
Fasdadasdfadsdfasdf asfsadafasdfasdffdaddad dads fdfgdfgfdg

Fdgdfgdfgdgfggggfg gdfgdfgd:
Fgdfgdfgdfgrdfhdf hdfgdfhdfh == fhdfgdfh /fhdgdg .
4 0
3 years ago
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