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emmasim [6.3K]
2 years ago
10

How many protons does Royalty, R-13, have?

Chemistry
1 answer:
dezoksy [38]2 years ago
4 0
19



please lmk if i was right:))
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Would the following atoms have similar reactivity?
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I think D, not sure though!
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(100 points) Atleast 5 slogans on saving fuel.
Inessa05 [86]

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Save Fuel, Save Earth

Fuel and time wait for none!

Be wise, don’t waste fuel

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Don’t contribute towards global warming

Care for future, save fuel

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Diagram of the outermost shell of fluorine atom?
Rufina [12.5K]

Orbital diagram:

\text{Energy}\left \uparrow \begin{array}{ccccc}2p & &\uparrow\downarrow&\uparrow\downarrow&\uparrow\\2s&\uparrow\downarrow\end{array}\right.

<h3>Explanation</h3>

Fluorine F is found in the second column from the right end of a modern periodic table. Fluorine is next to and on the left of the noble gas element neon. A neutral fluorine atom is one electron short of neon, which contains 8 electrons in the outermost shell when neutral. As a result, there are 7 electrons in the outermost shell of a fluorine atom.

Fluorine is in period 2. Its electrons occupy two main shells. The second main shell is the outermost shell of F. There are two subshells in the second main shell:

  • 2s, which holds up to two electrons, and
  • 2p, which holds up to six electrons.

A 2s electron carries less energy than a 2p electron. By Aufbau principle, the seven electrons will fill the two spaces in 2s before moving on the 2p. Among the 7 outermost shell electrons, 7 - 2 = 5 will end up going to 2p.

The only 2s orbital is filled with two electrons. The two 2s electrons will pair up with opposite spins, as seen with the two arrows. Two of the 2p orbitals will contain two electrons. Those electrons will also pair up. The third 2p orbital will contain only one electron. That electron can spin either \uparrow or \downarrow. Here that electron is shown as an upward arrow.

3 0
3 years ago
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Who is credited with developing a method that led to the determination of standard relative atomic masses
Pavel [41]

Answer:

Stanislao Cannizzaro

Explanation:

6 0
3 years ago
A sample consisting of 2 moles He is expanded isothermally at 0 degrees from 5.0dm3 to 20.0dm3. Calculate w, q and deltaU for ea
FinnZ [79.3K]

Answer:

i) \Delta U=0 w=-6293 J q=6293 J

ii) \Delta U=0 w=-3404,52 J q=3404,52 J

ii) \Delta U=0 w=0 J q=0 J

Explanation:

As the initial and final states of the sample are the same, the ΔU of the sample is, for the three cases

\Delta U=n.C_{V}.\Delta T=0 since \Delta T=0

i)Reversibly P_{ext} =P_{sys} so w can be calculated by  

w=-n.R.T.ln(\frac{V_{f}}{V_{i}})=-2 \times 8.314\frac{J}{mol K} \times 273,15K \times ln(\frac{}{5dm^{3}})=-6293 J

and because of the first law of thermodynamics

q=-w=6293 J

ii)Irreversibly with P_{ext} =P_{f}

we can calculate P_{f} by the law of ideal gases

P_{f} =\frac{n\times R\times T}{V_{f}} =\frac{2\times 0.082\frac{dm^{3}atm}{mol K}\times 273,15K}{20dm^{3}} =2,24 atm

then w can be calculated by

w=-P_{ext} \times \Delta V=-2,24 atm \times (20-5) dm^{3} \times frac{101.325J }{atm dm^{3}=-3404,52J

and  

q=-w=3404,52J

iii)a free expansion P_{ext} so w=0 (there's no work at vaccum) and q=-w=0

7 0
3 years ago
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