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Juliette [100K]
3 years ago
10

Which of the following is an example of non-matter?

Chemistry
2 answers:
Naddik [55]3 years ago
8 0
A: Light












it has to be 20 characters
Lera25 [3.4K]3 years ago
4 0

A!

stay safe and have a great day<8

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If 3.53 g of CuNO, is dissolved in water to make a 0.330 M solution, what is the volume of the solution in milliliters?
solmaris [256]

Answer:

84.8 mL

Explanation:

From the question given above, the following data were obtained:

Mass of CuNO₃ = 3.53 g

Molarity of CuNO₃ = 0.330 M

Volume of solution =?

Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:

Mass of CuNO₃ = 3.53 g

Molar mass of CuNO₃ = 63.5 + 14 + (16×3)

= 63.5 + 14 + 48

= 125.5 g/mol

Mole of CuNO₃ =?

Mole = mass / Molar mass

Mole of CuNO₃ = 3.53 / 125.5

Mole of CuNO₃ = 0.028 moles

Next, we shall determine the volume of the solution. This can be obtained as follow:

Molarity of CuNO₃ = 0.330 M

Mole of CuNO₃ = 0.028 moles

Volume of solution =?

Molarity = mole /Volume

0.330 = 0.028 / Volume

Cross multiply

0.330 × Volume = 0.028

Divide both side by 0.330

Volume = 0.028 / 0.330

Volume = 0.0848 L

Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.0848 L = 0.0848 L × 1000 mL / 1 L

0.0848 L = 84.8 mL

Therefore, the volume of the solution is 84.8 mL.

8 0
3 years ago
What is oxidized in a galvanic cell with aluminum and gold electrodes ?
k0ka [10]

Answer:

Aluminum metal

Explanation:

In order to properly answer this or a similar question, we need to know some basic rules about galvanic cells and standard reduction potentials.

First of all, your strategy would be to find a trusted source or the table of standard reduction potentials. You would then need to find the half-equations for aluminum and gold reduction:

Al^{3+}+3e^-\rightarrow Al; E^o=-1.66 V

Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Since we have a galvanic cell, the overall reaction is spontaneous. A spontaneous reaction indicates that the overall cell potential should be positive.

Since one half-equation should be an oxidation reaction (oxidation is loss of electrons) and one should be a reduction reaction (reduction is gain of electrons), one of these should be reversed.

Thinking simply, if the overall cell potential would be obtained by adding the two potentials, in order to acquite a positive number in the sum of potentials, we may only reverse the half-equation of aluminum (this would change the sign of E to positive):Al\rightarrow Al^{3+}+3e^-; E^o=1.66 V\\Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Notice that the overall cell potential upon summing is:

E_{cell}=1.66 V + 1.50 V=3.16 V

Meaning we obey the law of galvanic cells.

Since oxidation is loss of electrons, notice that the loss of electrons takes place in the half-equation of aluminum: solid aluminum electrode loses 3 electrons to become aluminum cation.

6 0
3 years ago
Is a cube of salt being crushed before being stirred into water a physical or chemical change
Olin [163]
By crushing the salt, you are performing a physical change because you aren't altering the chemical makeup of the salt, just the physical form. Hope this helps! :)
6 0
3 years ago
Read 2 more answers
I WILL GIVE BRAINLIEST PLEASE DO IT RIGHT!!! 1) Using the data below, create two simple line graphs on a separate sheet of paper
VLD [36.1K]

Answer:Score” scatter plot shows an example of a positive relationship—as one variable increases, so does the other. The points in this type of scatter plot tend to go “uphill” from left to right

Explanation:Score” scatter plot shows an example of a positive relationship—as one variable increases, so does the other. The points in this type of scatter plot tend to go “uphill” from left to right

3 0
3 years ago
If .680 g/L of a gas is dissolved in water at 5.00 atm of pressure, how much will dissolve (in g/L) at 8.00 atm of pressure.
KatRina [158]

Density and pressure are directly proportional

\\ \rm\Rrightarrow \rho_1P_2=\rho_2P_1\\ \rm\Rrightarrow 0.680(8)=5\rho_2

\\ \rm\Rrightarrow 5.44=5\rho_2

\\ \rm\Rrightarrow \rho_2=1.088g/\ell

5 0
2 years ago
Read 2 more answers
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