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GrogVix [38]
3 years ago
9

How much force is needed to have a 50 kg object accelerate at a rate of 5 m/s²?

Physics
1 answer:
Galina-37 [17]3 years ago
3 0
<span> (13.89 - 5.56) m/s /30 s = 8.33 / 30 = 0.278 m/s^2 </span>

<span>F = MA </span>
<span>F = 150 kg * 0.278 = 41.65 N  </span>

<span>#2) Newton's Equations of motion </span>

<span>distance = 0.5 * acceleration * time^2 + original velocity * time </span>
<span>velocity = acceleration * time + original velocity </span>

<span>First we need acceleration </span>

<span>F = MA </span>
<span>7 N = 0.4 kg*A (NOTE: I converted to consistent units: kg, m, s) </span>
<span>A = 7/.4 = 17,5 m/s^2 </span>

<span>V = at + Vo </span>
<span>80 m/s = 17.5 /s^2 * t + 0 (Started at rest) </span>

<span>80 = 17.5 t </span>
<span>t = 4.57 s </span>

<span>#3 </span>

<span>First we need the weight of the book on the floor </span>

<span>F = MA (A = 9.8 m/s^2 the acceleration of gravity) </span>
<span>F = 0.4 kg * 9.8 m/s^2 = 3.92 N </span>

<span>Now we need the Net Force on the book slowing it down (A = - 1.5 m/s^2) </span>


<span>F = MA </span>
<span>F = 0.4 kg * 1.5 m/s^2 = 0.6 N </span>

<span>===> Friction is 0.6 N greater than your push or 5.6 N </span>

<span>Weird!!! That means friction is greater than the weight of the book </span>

<span>Mu (coff of friction) = Friction Force/Weight = 5.6 / 3.92 = 1,43 ( Nonsense answer) </span>

<span>#4 We can do as a ratio </span>

<span>70/400 = 1500/x </span>
<span>70 x = 600,000 </span>
<span>x = 8,571 N</span>
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v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{2.8-0}{2.1}\\\Rightarrow a=1.33\ m/s^2

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v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{2.8^2-0^2}{2\times 1.33}\\\Rightarrow s=2.94\ m

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