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3 years ago

How much momentum is possessed by a 2,300 kg race car that is traveling down a race track at 20 m/s?

Physics

1 answer:

vodka [1.7K]3 years ago

4 0

The momentum of the car is 46,000 kg m/s

Explanation:

The momentum of an object is given by

$p=mv$

where

m is the mass of the object

v is its velocity

For the race car in the problem, we have:

m = 2,300 kg is the mass

v = 20 m/s is the velocity

Solving for the momentum, we find

$p=(2300)(20)=46000 kg m/s$

Learn more about momentum here:

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Refer to Concept Simulation 4.4 for background relating to this problem. The drawing shows a large cube (mass = 28.9 kg) being a

Usimov [2.4K]

Answer:

smallest magnitud is P=33.3 N

Explanation:

We are analyze the situation as an external force is applied and there is a friction force. We have a problem with Newton's second law.

F = ma

As the two blocks go together they must have the same acceleration, so we can calculate this for the entire system

P = (m1 + m2) a

a = P / (m1 + m2)

In this case there is no friction force because the small block does not touch the ground.

In order to calculate the friction force, we must analyze each system component separately.

The large block on the X axis has an applied P force and as it moves feels a force from the small block. In the Y axis has the weight (W1) and the reaction to normal (N1)

For the small block on the X axis, the force it feels is the thrust of the large block, note that this is an action and reaction force between the two blocks, it is the same definition we have of the normal one, so we can call this force (N)

Y axis it has the weight (W2) down, the force of friction (fr) that opposes the movement, so it is directed upwards. we write these equations

N = m2 a

fr -W2 = 0

fr = W2

The definition of friction force is

fr = μ N

Let's replace and calculate

μ (m2 a) = m2 g

μ (P / (m1 + m2)) = g

P = g /μ (m1 + m2)

Let's calculate the value of this force

P = 9.8 / 0.710 (28.9 +4.4)

P = 13.80 (33.3)

P = 33.3 N

This is the minimum friction force that prevents the block from sliding down

6 0

3 years ago

A basketball player jumps straight up with a speed of 14 m/s. How high did the player jump?

alexira [117]

Answer:

The basketball player jumped 10 m high.

Explanation:

Vertical Launch Upwards

In a vertical launch upwards, an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

$\displaystyle h_m=\frac{v_o^2}{2g}$

The basketball player jumps up with a speed of vo=14 m/s. The maximum height is:

$\displaystyle h_m=\frac{14^2}{2*9.8}$

$\displaystyle h_m=\frac{196}{19.6}=10$

The basketball player jumped 10 m high.

7 0

3 years ago

How is velocity different from speed?

enyata [817]

Velocity, unlike speed, includes a direction.

Velocity is a vector quantity which is defined by magnitude and direction.

Speed is a scalar quantity. It is the rate at which an object moves regardless of which direction.

5 0

3 years ago

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You're in a car that gets 28 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and

Nataly [62]

Answer:

The diameter of the hose is 0.326 mm.

Explanation:

Given that,

Speed of car = 28 miles/galllon

We need to calculate the radius

The rate of flow of fluid is from the equation of continuity

$\dfrac{V}{t}=Av$

Where, A = area of cross sectional

$\dfrac{V}{t}=\pi r^2v$

We know that,

The velocity is the ratio of displacement of gas per unit time.

$\dfrac{V}{t}=\pi r^\dfrac{x}{t}$

$\dfrac{V}{x}=\pi r^2$

Put the value into the formula

$\dfrac{0.00378541}{28\times1609.34}=\pi r^2$

$r=\sqrt{\dfrac{0.00378541}{28\times1609.34\times\pi}}$

$r=1.63\times10^{-4}\ m$

We need to calculate the diameter of the hose

$d = 2r$

Put the value of r

$d=2\times1.63\times10^{-4}$

$d=0.326\ mm$

Hence, The diameter of the hose is 0.326 mm.

6 0

3 years ago

Please help...........................

Marianna [84]

Hi!

Neutrons are neutral, which means they don't exactly have an electrical charge. It's because of this neutral charge that it is represented with a '0'.

On the other hand, protons and electrons do have electrical charges. Electrons flow around the outside of the nucleus, with a negative charge.

Protons are stored in the nucleus with the neutrons, holding a positive charge.

Hopefully, this helps! =)

6 0

4 years ago

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