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soldi70 [24.7K]
3 years ago
12

Please answer help me

Physics
1 answer:
bixtya [17]3 years ago
6 0
Object 5 &1 I’m pretty sure those numbers can’t hold up an moon.
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A satellite orbits the Earth in an elliptical orbit. At perigee its distance from the center of the Earth is 22500 km and its sp
aleksley [76]

Answer:

6.09294\times 10^{24}\ kg

Explanation:

K = Kinetic energy

v_p = Perigee speed = 4280 m/s

v_a = Apogee speed = 3990 m/s

r_p = Perigee Distance = 22500000 m

r_a = Apogee Distance = 24100000 m

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Earth

m = Mass of satellite

In this system the kinetic and potential energies are conserved

K_p+P_p=K_a+P_a\\\Rightarrow \frac{1}{2}mv_p^2-\frac{GMm}{r_p}=\frac{1}{2}mv_a^2-\frac{GMm}{r_a}\\\Rightarrow \frac{1}{2}m(v_p^2-v_a^2)+GMm\left(\frac{1}{r_a}-\frac{1}{r_p}\right)=0\\\Rightarrow M=\frac{v_a^2-v_p^2}{2G}\times \left(\frac{1}{r_a}-\frac{1}{r_p}\right)^{-1}\\\Rightarrow M=\frac{3990^2-4280^2}{2\times 6.67\times 10^{-11}}\times \left(\frac{1}{24100000}-\frac{1}{22500000}\right)^{-1}\\\Rightarrow M=6.09294\times 10^{24}\ kg

The mass of the Earth is 6.09294\times 10^{24}\ kg

3 0
4 years ago
A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its maximum displacement from
kaheart [24]

Answer:

zero

Explanation:

In this system, only conservative forces act. Therefore, the mechanical energy, that is, the sum of the kinetic energy and the potential energy, remains constant. When the mass is at its maximum displacement from equilibrium, its potential energy is maximum, therefore, its kinetic energy is minimal, that is to say, that its instantaneous velocity at that point is zero.

6 0
3 years ago
Solving equation for the quantity indicated
Slav-nsk [51]
T = (vf -vo)/a. .......
7 0
3 years ago
Read 2 more answers
In Fig.25-46,how much charge is stored on the parallel-plate capacitors by the 12.0 V battery? One is filled with air,and the ot
Fittoniya [83]

Answer:

Q=7.9\times 10^{-10}\ C

Explanation:

Given that

V= 12 V

K=3

d= 2 mm

Area=5.00 $ 10#3 m2

Assume that

$ = Multiple sign

# = Negative sign

A=5\times 10^{-3}\ m^2

We Capacitance given as

For air

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}

C_1=2.2\times 10^{-11}\ F

C_2=\dfrac{K\varepsilon _oA}{d}

C_2=\dfrac{3\times 8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}\ F

C_2=6.6\times 10^{-11}\ F

Net capacitance

C=C₁+C₂

C=8.8\times 10^{-11}\ F

We know that charge Q given as

Q= C V

Q=12\times 6.6\times 10^{-11}\ C

Q=7.9\times 10^{-10}\ C

6 0
3 years ago
A force of attraction would exist between
siniylev [52]

Answer:

A. positively charged object and a negatively charged object.

3 0
4 years ago
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