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Crank
3 years ago
5

The product of m1m2 in the formula for gravitational force is always

Physics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

The correct answer is the second option

Explanation:

The formula in question (for gravitational force) is provided below

F = G.m₁.m₂/r²

Where

F = force of gravity

G = gravity constant (6.674 × 10⁻¹¹ m.kg⁻¹.s⁻²)

m₁ and m₂ = are the masses of the objects

r² = distance between the centers of the two objects

From the above, <u>it can be deduced that m₁ and m₂ are masses and hence can only be positive. Positives multiplied together only gives positive, thus the second option is correct.</u>

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A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?
Snowcat [4.5K]

Answer:

6.07 N

Explanation:

Given that,

Force, F = 35 N

It makes 10 degree angle with the positive x-axis.

We need to find the magnitude of the vertical component of the force. It can be given by :

F_y=F\sin\theta\\\\=35\times \sin(10)\\\\=6.07\ N

So, the magnitude of the vertical component of the force is 6.07 N.

5 0
3 years ago
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What is the length of a string with a mass of 2.5 kg, with a
TiliK225 [7]

Answer:

.5 m

Explanation:

It is correct lol.

8 0
3 years ago
A 34-kg child on an 18-kg swing set swings back and forth through small angles. If the length of the very light supporting cable
kompoz [17]

Answer:

4.44s

Explanation:

A 34-kg child on an 18-kg swing set swings back and forth through small angles. If the length of the very light supporting cables for the swing is 4.9 m, how long does it take for each complete back-and-forth swing? Assume that the child and swing set are very small compared to the length of the cables

since the mass of the child and that of the swing is negligible, the masses wont be involved in the calculation

T=2π√L/g

g=acceleration due to gravity which is 9.81m/s2

the length of the supporting cable is 4.9m

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period is the time required to make a complete oscillation

T=2*π√4.9/9.81

T=2*π*0.706

T=4.44s

4.44s

5 0
3 years ago
A 4kg rock isn’t rolling 10m/s. Find it’s kinetic energy.
scoundrel [369]

Kinetic energy = (1/2) (mass) (speed)²

The rock's kinetic energy is not 

                           (1/2) (4 kg) (10 m/s)²

                      =   (1/2) (4 kg) (100 m²/s²)

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It may be more, or it may be less.  The only thing
we can be sure of is that it is not 200 Joules.
3 0
3 years ago
in a softball game, a batter hits the ball at the velocity of 27m/s and angle of 40 shown below. What is the maximum range of th
Nata [24]

Answer:

R = 73.25 m

Explanation:

We have,

Initial speed of the ball is 27 m/s

It is projected at an angle of 40 degrees

The maximum range of the ball is given by :

R=\dfrac{u^2\sin2\theta}{g}

Plugging all the values we get :

R=\dfrac{(27)^2\sin2(40)}{9.8}\\R=73.25\ m

So, the maximum range of the ball is 73.25 m

8 0
3 years ago
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