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Crank
4 years ago
5

The product of m1m2 in the formula for gravitational force is always

Physics
1 answer:
Nataly [62]4 years ago
8 0

Answer:

The correct answer is the second option

Explanation:

The formula in question (for gravitational force) is provided below

F = G.m₁.m₂/r²

Where

F = force of gravity

G = gravity constant (6.674 × 10⁻¹¹ m.kg⁻¹.s⁻²)

m₁ and m₂ = are the masses of the objects

r² = distance between the centers of the two objects

From the above, <u>it can be deduced that m₁ and m₂ are masses and hence can only be positive. Positives multiplied together only gives positive, thus the second option is correct.</u>

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Whais the cause of necular bomb ​
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Explanation:

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2 years ago
A teacup on a spinning teacup ride takes 1.5 s to complete a revolution around the center of the platform. What is the centripet
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3 years ago
Read 2 more answers
the displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s
12345 [234]

The average velocity or displacement of a particle for the first time interval is <u>Δs / Δt = 6 cm/s.</u>

Solution:

As we know that displacement is calculated in centimeters and the unit of time is second.

The average velocity for the first interval [1,2] is given

Δs / Δt = s (t2) - s (t) / t2 - t1

Δs / Δt = 2sin2  π  + 3cos 2 π -  ( 2sin π + 3cos π ) / 2 - 1

Δs / Δt = 2(0) + 3(1) - 2(0) - 3 (-1) / 1

Δs / Δt = 6 cm/s

Thus the average velocity or displacement of a particle for the first time interval is Δs / Δt = 6 cm/s

If you need to learn more about displacement click here:

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The complete question is:

The displacement of a particle moving back and forth along a line is given by the following equation s(t) = 2sin π t + 3cos π t. Estimate the instantaneous velocity of the particle when t = 1

4 0
2 years ago
What is the fundamental frequency (in Hz) of a 0.632 m long tube, open at both ends, on a day when the speed of sound is 344 m/s
Greeley [361]

Answer:

f=272.15Hz

Explanation:

Given data

Length of tube L=0.632 m

Speed of sound v=344 m/s

To find

Fundamental frequency f

Solution

The fundamental frequency of the tube can be given as:

f=\frac{v}{2L}\\ f=\frac{344m/s}{2(0.632m)}\\ f=272.15Hz

4 0
4 years ago
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