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3 years ago

An iron nail is made up of particles. What is true about the particles?Why does ice float on water?

1 answer:

4 0

Answer: i know that ice is denser than water because of the reason why ice is expanding:air. ice has tiny air packets inside that make it bigger than the original state(the state which a substance is at at room temperature.

Explanation:

Iron is an element that has been known in its pure form for at least 5,000 years. The name "iron" comes from the...

The element symbol for iron is Fe, which comes from the Latin word for iron, "ferrum."

Iron is one of the most plentiful elements. It comprises about 5.6 percent of the Earth's crust and almost all of its core

Iron is a transition metal.

Animals and plants require iron. Plants use iron in chlorophyll, the pigment used in photosynthesis. Humans use iron in hemoglobin molecules in blood to allow for the transport of oxygen to tissues throughout the body.

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A constant torque of 26.6 N · m is applied to a grindstone for which the moment of inertia is 0.162 kg · m2 . Find the angular s

ozzi

Answer:

156.1 rad/s = 24.8 rev/s

Explanation:

Torque = Momentum of inertial × radial acceleration = Iα

τ = 26.6 N.m

I = 0.162 kg.m²

26.6 = 0.162 × α

α = 164.2 rad/s²

Using equations of motion,

θ = 11.8 rev = 11.8 × 2π = 74.2 rad

w₀ = 0 rad/s (since the grindstone starts from rest)

w = ?

α = 164.2 rad/s²

w² = w₀² + 2(α)(θ)

w² = 0² + (2×164.2)(74.2)

w = 156.1 rad/s = 24.8 rev/s

Hope this Helps!!!

7 0

3 years ago

Read 2 more answers

Two parallel square metal plates that are 1.5 cm and 22 cm on each side carry equal but opposite charges uniformly spread out ov

Mumz [18]

Answer:

The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

Explanation:

Given that,

Distance =1.5 cm

Side = 22 cm

Electric field = 18000 N/C

We need to calculate the capacitance in the metal plates

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times(22\times10^{-2})^2}{1.5\times10^{-2}}$

$C=0.285\times10^{-10}\ F$

We need to calculate the potential

Using formula of potential

$V=Ed$

Put the value into the formula

$V=18000\times1.5\times10^{-2}\ V$

$V=270\ V$

We need to calculate the charge

Using formula of charge

$Q=CV$

Put the value into the formula

$Q=0.285\times10^{-10}\times270$

$Q=76.95\times10^{-10}\ C$

Here, the charge on both the positive and negative plates

$Q=+76.95\times10^{-10}\ C$

$Q=-76.95\times10^{-10}\ C$

We need to calculate the number of excess electrons are on the negative surface

Using formula of number of electrons

$n=\dfrac{q}{e}$

Put the value into the formula

$n=\dfrac{76.95\times10^{-10}}{1.6\times10^{-19}}$

$n=4.80\times10^{10}\ electrons$

Hence, The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

8 0

3 years ago

What is the effect of the mass of an object on it’s friction threshold?

Alina [70]

An object of large mass is pulled down onto a surface with a greater force than an object of low mass and, as a consequence, there is greater friction between the surface of the heavy object than between the surface and the light object.

6 0

3 years ago

A wire that has a resistance of 1Ω is to be built from an aluminum block of volume 1 cm3

alina1380 [7]

Answer:

L = 5,955 m

Explanation:

For this exercise we must use the relation

R = ρ L / A

where R is the resistance that indicates that it is 1 Ω, the resistivity is taken from the tables ρ = 2.82 10⁻⁸ Ω m, L is the length of the wire and A is the cross section.

As it indicates to us in volume of aluminum to use we divide the two terms by the length

R / L = ρ L / (A L)

the volume of a body is its area times its length, therefore

R / L = ρ L / V

R = ρ L² / V

we clear the length of the wire

L = √ R V /ρ

we reduce the volume to SI units

v = 1 cm³ (1m / 10² cm)³ = 1 10⁻⁶ m

let's calculate

L = √ (1 1 10⁻⁶ / 2.82 10⁻⁸)

L = √ (0.3546 10²)

L = 5,955 m

5 0

3 years ago

In your study unit, a relationship is compared to a car to point out that

mylen [45]

To point out that relationships call for regular maintenance. Cars need regular oil checkups and such and so do relationships.

Hope this helps :)

8 0

4 years ago