WHat's a concept map again?
I forgot...
Answer:
The solution will not form a precipitate.
Explanation:
The Ksp of PbI₂ is:
PbI₂(s) ⇄ 2I⁻(aq) + Pb²⁺(aq)
Ksp = 1.40x10⁻⁸ = [I⁻]²[Pb²⁺] <em>Concentrations in equilibrium</em>
When 328mL of 0.00345M NaI(aq) is combined with 703mL of 0.00802M Pb(NO₃)₂. Molar concentration of I⁻ and Pb²⁺ are:
[I⁻] = 0.00345M × (328mL / (328mL+703mL) =<em> 1.098x10⁻³M</em>
[Pb²⁺] = 0.00802M × (703mL / (328mL+703mL) =<em> 5.469x10⁻³M</em>
<em />
Q = [I⁻]²[Pb²⁺] <em>Concentrations not necessary in equilibrium</em>
If Q = Ksp, the solution is saturated, Q > Ksp, the solution will form a precipitate, if Q < Ksp, the solution is not saturated.
Replacing:
Q = [1.098x10⁻³M]²[5.469x10⁻³M] = 6.59x10⁻⁹
As Q < Ksp, the solution is not saturated and <em>will not form a precipitate</em>.
Answer:
• The closing of the frontier
Explanation:
• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier
Answer:
The volume of carbon (ii) oxide present is <u><em>2.80 L</em></u>
Explanation:
In this question, we are asked to calculate the volume of a certain number of moles of carbon (ii) oxide sealed in a container at STP
The equation to use here is the ideal gas equation.
Mathematically;
PV = nRT
since we are to calculate the volume, the equation can be re-written as
V = nRT/P
The values according to the question are as follows;
n is the number of moles which is 0.125 moles
T is the temperature at STP which is 0°C = 273.15 K(kelvin)
P is the pressure at STP which is 1.0 atm (atmosphere)
R is the molar gas constant which is 0.0821 L.atm.
Plugging these values, we have
V = (0.125 × 0.0821 × 273.15)/1 = 2.80 L
The law of conservation of mass states that mass cannot be created or destroyed. It can only be transformed/transferred from one form to another.