The time of motion of the track star is determined as 0.837 s.
<h3>Time of motion of the track star</h3>
The time of motion of the track star is calculated as follows;
T = (2u sinθ)/g
where;
- T is time of motion
- g is acceleration due to gravity
- θ is angle of projection
T = (2 x 12 x sin20)/9.8
T = 0.837 s
Learn more about time of motion here: brainly.com/question/2364404
#SPJ1
<span>division of Earth's history into time units based largely on the types of life-forms that lived only during certain periods.</span>
Answer:
Explanation:
N=Rotor Speed in Revolution per minute(rpm)
for P=4 and N=3600, f comes out to be 120 Hz.
So frequency of voltage produced is 120 Hz. But this is not practical. Generally 4-Pole generator has N=1500rpm(for 50 Hz) or 1800rpm for 60 Hz. Two pole generator can have N=3600rpm(f=60Hz).
The most practical situation is generator having N=3600Hz with 2 Poles.
Hope It will be helpful!!!
Answer:
diameter = 9.951 × 
m
Explanation:
given data
NA = 0.1
refractive index = 1.465
wavelength = 1.3 μm
to find out
What is the largest core diameter for which the fiber remains single-mode
solution
we know that for single mode v number is
V ≤ 2.405
and v = 
here r is radius
so we can say
= 2.405
put here value
= 2.405
solve it we get r
r = 4.975979 × 
m
so diameter is = 2 × 4.975979 × m
diameter = 9.951 × m
