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jok3333 [9.3K]
3 years ago
13

Plz help brainliest plzzzzzzzzzzzzzzzzz!!!!!!!!!!!!!!

Physics
1 answer:
Likurg_2 [28]3 years ago
8 0

Answer:

b

Explanation:

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Work and energy both have the unit?
sveta [45]
The both have the unit (J) for Jules
 
6 0
3 years ago
Two identical objects in outer space have a head-on collision and stick together. If, before the collision, one had been moving
julia-pushkina [17]

Answer:

1.5 m/s

Explanation:

Momentum is conserved and conservation of momentum is

p₁ + p₂ = p'₁ + p'₂

or

m₁v₁ + m₂v₂ = m₁v'₁  + m₂v'₂

In our problem, after collision v'₁ will be equal to v'₂.

Since objects are identical m₁ = m₂

m(v₁+ v₂) = 2m x v'₁

(2m/s + 1m/s) = 2v'₁

v'₁ = v'₂ = 1.5 m/s

5 0
3 years ago
A football is thrown due north across a 40 meter river and it takes 2 seconds to cover that distance.
Alexxx [7]

Answer:

I. Speed = 20m/s

II. Velocity = 20m/s due North.

Explanation:

<u>Given the following data;</u>

Distance = 40m

Time = 2secs

To find the speed;

Mathematically, speed is given by the formula;

Speed = \frac{distance}{time}

Substituting into the equation, we have;

Speed = \frac{40}{2}

<em>Speed = 20m/s.</em>

In physics, we use the same formula for calculating speed and velocity. The only difference is that speed is a scalar quantity and as such has magnitude but no direction while velocity is a vector quantity and as such it has both magnitude and direction.

Velocity = \frac{distance}{time}

<em>Therefore, the velocity is 20m/s due North</em>.

6 0
2 years ago
An experimental rocket designed to land upright falls freely from a height of 2.59 102 m, starting at rest. At a height of 86.9
aleksandr82 [10.1K]

Answer:

The acceleration required by the rocket in order to have a zero speed on touchdown is 19.96m/s²

The rocket's motion for analysis sake is divided into two phases.

Phase 1: the free fall motion of the rocket from the height 2.59*102m to a height 86.9m

Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 86.9m to the point of touchdown y = 0m.

Explanation:

The initial velocity of the rocket is 0m/s when it started falling from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.

The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.

The detailed step by step solution to the problems can be found in the attachment below.

Thank you and I hope this solution is helpful to you. Good luck.

5 0
2 years ago
Am 1 years old UwU (JK 15)
igomit [66]

Answer:

so am i ._. 15 not 1 ofc lol

Explanation:

7 0
2 years ago
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