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Answer:
(b) By including a statement that he or she is licensed by the Board for Professional Engineers and Land Surveyors immediately above the signature line in at least 12 point type on all contracts for services
Explanation:
A PE(professional engineer) licensee must show that he is licensed in order to show and ensure public safety as he is qualified for the job he is handling. The California regulations on professional engineers holds that all professional engineers must be licensed by the board of professional engineers and Land surveyors in order to operate legally as an engineer. The engineer may show licensure through the following options:
The engineer might provide statement to each client to show he is licensed which would then be signed by the client
The engineer may choose to post a wall certificate in his work premises to show he is licensed
The engineer may choose to include a statement of license in a letterhead or contract document which must be above the client's signature line and not less than 12 point type
Answer:
a) 0.697*10³ lb.in
b) 6.352 ksi
Explanation:
a)
For cylinder AB:
Let Length of AB = 12 in
![c=\frac{1}{2}d=\frac{1}{2} *1.1=0.55in\\ J=\frac{\pi c^4}{2}=\frac{\pi}{2}0.55^4=0.1437\ in^4\\](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B1%7D%7B2%7Dd%3D%5Cfrac%7B1%7D%7B2%7D%20%2A1.1%3D0.55in%5C%5C%20J%3D%5Cfrac%7B%5Cpi%20c%5E4%7D%7B2%7D%3D%5Cfrac%7B%5Cpi%7D%7B2%7D0.55%5E4%3D0.1437%5C%20in%5E4%5C%5C)
![\phi_B=\frac{T_{AB}L}{GJ}=\frac{T_{AB}*12}{3.3*10^6*0.1437} =2.53*10^{-5}T_{AB}](https://tex.z-dn.net/?f=%5Cphi_B%3D%5Cfrac%7BT_%7BAB%7DL%7D%7BGJ%7D%3D%5Cfrac%7BT_%7BAB%7D%2A12%7D%7B3.3%2A10%5E6%2A0.1437%7D%20%20%3D2.53%2A10%5E%7B-5%7DT_%7BAB%7D)
For cylinder BC:
Let Length of BC = 18 in
![c=\frac{1}{2}d=\frac{1}{2} *2.2=1.1in\\ J=\frac{\pi c^4}{2}=\frac{\pi}{2}1.1^4=2.2998\ in^4\\](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B1%7D%7B2%7Dd%3D%5Cfrac%7B1%7D%7B2%7D%20%2A2.2%3D1.1in%5C%5C%20J%3D%5Cfrac%7B%5Cpi%20c%5E4%7D%7B2%7D%3D%5Cfrac%7B%5Cpi%7D%7B2%7D1.1%5E4%3D2.2998%5C%20in%5E4%5C%5C)
![\phi_B=\frac{T_{BC}L}{GJ}=\frac{T_{BC}*18}{5.9*10^6*2.2998} =1.3266*10^{-6}T_{BC}](https://tex.z-dn.net/?f=%5Cphi_B%3D%5Cfrac%7BT_%7BBC%7DL%7D%7BGJ%7D%3D%5Cfrac%7BT_%7BBC%7D%2A18%7D%7B5.9%2A10%5E6%2A2.2998%7D%20%20%3D1.3266%2A10%5E%7B-6%7DT_%7BBC%7D)
![2.53*10^{-5}T_{AB}=1.3266*10^{-6}T_{BC}\\T_{BC}=19.0717T_{AB}](https://tex.z-dn.net/?f=2.53%2A10%5E%7B-5%7DT_%7BAB%7D%3D1.3266%2A10%5E%7B-6%7DT_%7BBC%7D%5C%5CT_%7BBC%7D%3D19.0717T_%7BAB%7D)
![T_{AB}+T_{BC}-T=0\\T_{AB}+T_{BC}=T\\T_{AB}+T_{BC}=14*10^3\ lb.in\\but\ T_{BC}=19.0717T_{AB}\\T_{AB}+19.0717T_{AB}=14*10^3\\20.0717T_{AB}=14*10^3\\T_{AB}=0.697*10^3\ lb.in\\T_{BC}=13.302*10^3\ lb.in](https://tex.z-dn.net/?f=T_%7BAB%7D%2BT_%7BBC%7D-T%3D0%5C%5CT_%7BAB%7D%2BT_%7BBC%7D%3DT%5C%5CT_%7BAB%7D%2BT_%7BBC%7D%3D14%2A10%5E3%5C%20lb.in%5C%5Cbut%5C%20T_%7BBC%7D%3D19.0717T_%7BAB%7D%5C%5CT_%7BAB%7D%2B19.0717T_%7BAB%7D%3D14%2A10%5E3%5C%5C20.0717T_%7BAB%7D%3D14%2A10%5E3%5C%5CT_%7BAB%7D%3D0.697%2A10%5E3%5C%20lb.in%5C%5CT_%7BBC%7D%3D13.302%2A10%5E3%5C%20lb.in)
b) Maximum shear stress in BC
![\tau_{BC}=\frac{T_{BC}}{J}c=13.302*10^3*1.1/2.2998=6.352\ ksi](https://tex.z-dn.net/?f=%5Ctau_%7BBC%7D%3D%5Cfrac%7BT_%7BBC%7D%7D%7BJ%7Dc%3D13.302%2A10%5E3%2A1.1%2F2.2998%3D6.352%5C%20ksi)
Maximum shear stress in AB
![\tau_{AB}=\frac{T_{AB}}{J}c=0.697*10^3*0.55/0.1437=2.667\ ksi](https://tex.z-dn.net/?f=%5Ctau_%7BAB%7D%3D%5Cfrac%7BT_%7BAB%7D%7D%7BJ%7Dc%3D0.697%2A10%5E3%2A0.55%2F0.1437%3D2.667%5C%20ksi)
Answer:
Teller, Loan Officer, and Tax Preparer
Explanation: