Answer:
X = 4
Explanation:
Start 2800
End 175
175 = 2800x(0.5)^X
175/2800 = 0.5^X
0.0625 = 0.5^X
log(0.5 x) = log(0.0625)
x · log(0.5) = log(0.0625)
-0.301x = -1.204
x = -1.204/-0.301
x = 4
Answer:
1.44 mol
Explanation:
Given data:
Mass of Cu = 46 g
Moles of Ag produced = ?
Solution:
Chemical equation:
Cu + 2AgNO₃ → 2Ag + Cu(NO₃)₂
Number of moles of Cu:
Number of moles = mass/ molar mass
Number of moles = 46 g/63.546 g/mol
Number of moles = 0.72 mol
Now we will compare the moles of Cu and silver from balance chemical equation:
Cu : Ag
1 : 2
0.72 : 2×0.72 = 1.44 mol
Thus from 46 g of Cu 1.44 moles of Ag is produced .
Answer: 14.3%Explanation: In order to find the mass percent of hydrogen in this compound, you must determine how many grams of hydrogen you'd get in 100 g of compound.
In your case, you know that an unknown mass of hydrogen reacts with 0.771 g of carbon to form 0.90 g of hydrocarbon, which is a compound that contains only carbon and hydrogen.
Use the total mass of the hydrocarbon to determine how many grams of hydrogen reacted with the carbon.
Now, if 0.90 g of this compound contain 0.129 g of hydrogen, it follows that 100 g of this compound will contain.
So, if 100 g of this compound contain 14.33 g of hydrogen, it follows that the mass percent of hydrogen is 14.3%
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Answer:
Single Displacement Reaction: a reaction in which an element is swapped for another in a molecule
A + BC ---> AC + B
Double Displacement Reaction: a reaction in which the cation of one molecule is swapped with a cation of another molecule
AB + CD ---> AD + CB
a) Single Displacement Reaction
3 Ca + 2 AlBr₃ ----> 3 CaBr₂ + 2 Al
b) Single Displacement Reaction
2 Al + 3 MgSO₄ ----> Al₂(SO₄)₃ + 3 Mg
c) Double Displacement Reaction
AgNO₃ + KCl ----> AgCl + KNO₃
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