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Kaylis [27]
3 years ago
9

Every 10 seconds a pendulum makes 2 cycles. What are the period and frequency of this pendulum

Physics
1 answer:
jek_recluse [69]3 years ago
5 0

   (10 seconds) / (2 cycles)  =  (10/2) (sec/cycle) = 5 seconds.

That's the pendulum's period.

Frequency = 1 / (period) = 1/5 per second  =  0.2 Hz.

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A(n) 131 g ball is dropped from a height
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Answer:

26.59 N/m

Explanation:

From the question given above, the following data were obtained:

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Therefore,

131 g = 131 g × 1 Kg / 1000 g

131 g = 0.131 Kg

Thus, 131 g is equivalent to 0.131 Kg.

Next, we shall the force exerted by the ball on the spring. This can be obtained as follow:

Mass (m) = 0.131 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = ma

F = 0.131 × 9.8

F = 1.2838 N

Next, we shall convert 4.82755 cm to metre (m)

This can be obtained as follow:

100 cm = 1 m

Therefore,

4.82755 cm = 4.82755 cm × 1 m / 100 cm

4.82755 cm = 0.0482755 m

Thus, 4.82755 cm is equivalent to 0.0482755 m

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Force (F) = 1.2838 N

Extention (e) = 0.0482755 m

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F = Ke

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Divide both side by 0.0482755

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